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Kitty [74]
3 years ago
15

3ab+2cb,3ca-ab+2bc+3ab-ca please do step by step ​

Mathematics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

3ab+2cb,2ca+2ab+2bc

Step-by-step explanation:

1. Collect like terms.

3ab+2cb,((3ca-ca)+(-ab+3ab)+2bc)

3ab+2cb,((3ca−ca)+(−ab+3ab)+2bc)

2. Simplify  (3ca-ca)+(-ab+3ab)+2bc(3ca−ca)+(−ab+3ab)+2bc  to  2ca+2ab+2bc2ca+2ab+2bc.

3ab+2cb,2ca+2ab+2bc

3ab+2cb,2ca+2ab+2bc

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5 0
3 years ago
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Luda [366]

You used the fact that you can multiply both sides of an equality by the same, non-zero constant.

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4 years ago
Please help <br><br> asap plz!!
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7 0
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