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olasank [31]
3 years ago
14

A body of mass 60kg is displaced through 90m in 4 second when force is applied to it.calculate acceleration and the force applie

d​
Physics
1 answer:
arsen [322]3 years ago
4 0

Answer:

force=337.5N

accelertion=5.63ms^-2

Explanation:

please find the answers in the pictures above maam or sir.

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HELP ASAP!!!!!!! PLEASE WILL GIVE BRAINLIEST
Pani-rosa [81]

Answer:

The three major parts of a cell are:

a. Cell membrane

b. Nucleus

c. Cytoplasm

Explanation:

a. Cell membrane:

It provides protection for a cell.

b. Nucleus:

It controls and regulates the activities of cell.

c. Cytoplasm:

It supports and suspends organelles and cellular molecules.

8 0
3 years ago
Read 2 more answers
Need help asap pls
ozzi
Detailed Explanation:

1) Rusting of Iron

4Fe + 3O2 + 2H2O -> 2Fe2O32H2O

Reactants :-
Fe = 4
O = 3 * 2 + 2 = 8
H = 2 * 2 = 4

Products :-
Fe = 2 * 2 = 4
O = 2 * 3 + 2 = 8
H = 2 * 2 = 4

2) Fermentation of sucrose…

C12H22O11 + H2O -> 4C2H5OH + 4CO2

Reactants :-
C = 12
H = 22 + 2 = 24
O = 11 + 1 = 12

Products :-
C = 4 * 2 + 4 = 12
H = 4 * 5 + 4 = 24
O = 4 * 2 + 4 = 12

Looking closely at the way I have taken the total number of elements on the reactants and products side, you can solve the rest.

All the Best!
8 0
3 years ago
Read 2 more answers
A 650-kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruis- ing speed
Nataly_w [17]

Answer: P=5573.43\ W

Explanation:

Given

Mass of the elevator is M=650\ kg\\\

Time period of ascension t=3\ s

cruising speed v=1.75\ m/s

Distance moved by elevator during this time

Suppose Elevator starts from rest

\Rightarrow v=u+at\\\Rightarrow 1.75=0+a(3)\\\Rightarrow a=0.583\ s

Distance moved

\Rightarrow h=ut+0.5at^2\\\Rightarrow h=0+0.5\times 0.5833\times (3)^2\\\Rightarrow h=2.62\ m

Gain in Potential Energy is

\Rightarrow E=mgh\\\Rightarrow E=650\times 9.8\times 2.62\\\Rightarrow E=16,720.3\ N

Average power during this period is

\Rightarrow P=\dfrac{E}{t}\\\\\Rightarrow P=\dfrac{16,720.3}{3}\\\\\Rightarrow P=5573.43\ W

7 0
3 years ago
Read 2 more answers
How many turns should a 10-cm long solenoid have if it is to generate a 1.5 x 10-3 t magnetic field on 1.0 a of current?
stepan [7]

We can answer this problem using Ampere’s Law:

<span>Bh = μoNI </span>

Where:

B = Magnetic Field

h = coil length

<span>μo = permeability =4π*10^-7 T·m/A </span>

N = number of turns

I = current

It is given that B=0.0015T, I=1.0A, h=10 cm = 0.1m<span>

Use Ampere's law to find # turns: 
Which can be rewritten as: 
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0) 
N = 119.4 

</span>

<span>Answer: 119.4 turns</span>

3 0
3 years ago
a projectile leaves the ground with a velocity of 35 meters per second at an angle 32° what is the maximum height
Nina [5.8K]
To determine the maximum height for the projectile, we can use the timeless kinematics equation V _{f} ^{2} -V_{i}^{2}=2a \Delta y and plug in what we know. For V _{f} ^{2}, we know it is zero because at the highest location of flight, there is no vertical velocity. For V _{i} ^{2}, we know it is (35sin(32))^{2} since the vertical component is the sine of the velocity. We need to solve for y, so it is left as-is. Since the only acceleration is g, we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for \Delta y.
6 0
4 years ago
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