A particle is moving along the x-axis so that its position at any time t is greater than and equal to 0 is given by x(t)=2te^-t?

1 answer:

6 0

For speed you can differentiate the equation, for acceleration you can again differentiate the equation .
at t=0 the particle is slowing down , when you get equation for velocity put t=0 then only -1 is left

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krek1111 [17]

Answer:

Explanation:

a vector quantity has both magnitude and direction

6 0

3 years ago

An object is pulled to the left by a force of 50 N. The same amount of force pulls it to the right. The object will ____.

11111nata11111 [884]

<h2>Required Answer:</h2>

The body will stay at rest (Option D). It is because a force of magnitude 50 N is pulled towards left and another force is pulling it towards right with same magnitude 50 N. So, the direction of force is opposite and magnitude is same i.e. 50 N. So, they will cancel each other and net force is 0. Hence, there would be no acceleration.

Option A - Showing acceleration
Option B - Showing acceleration
Option C - Change of direction due to Net force

Hence, these options are incorrect because they are only possible when net external force is non-zero. Staying at rest i.e. Option D means there is no motion and hence no acceleration, this shows that net force is 0 $.$

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3 0

3 years ago

An ideal gas is confined within a closed cylinder at atmospheric pressure (1.013 * 105 Pa) by a piston. The piston moves until t

likoan [24]

Answer:

$911700\ \text{Pa}$

Explanation:

$P_1$ = Initial pressure = $1.013\times 10^5\ \text{Pa}$

$V_1$ = Initial volume

$V_2$ = Final volume = $\dfrac{V_1}{9}\\\Rightarrow \dfrac{V_1}{V_2}=9$

Temperature is the same in the initial and final state

From the ideal gas law we have

$P_1V_1=P_2V_2\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=P_1\times9\\\Rightarrow P_2=1.013\times 10^5\times 9\\\Rightarrow P_2=911700\ \text{Pa}$