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liraira [26]
2 years ago
14

How much protons are in Li

Physics
2 answers:
harkovskaia [24]2 years ago
6 0

Answer: 3

Explanation:

Lithium always has 3 protons bc it’s atomic number is 3 which is determined by its amount of protons.

V125BC [204]2 years ago
6 0

The number of protons from the element Lithium (Li) is <u>3</u>

<h3>Further explanation </h3>

The Atomic Number (Z) indicates the number of protons in an atom of an element. If the atom is neutral then the number of protons will be equal to the number of electrons. So the atomic number can also indicate the number of electrons.

 So atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Mass Number (A) = Number of protons + Number of Neutrons

So that the relationship between atomic numbers and mass numbers can be formulated as follows:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons

In the following element notation,

\large {{{A} \atop {Z}} \right X}

X = symbol of elemental atom

A = mass number

   = number of protons + number of neutrons

Z = atomic number

   = number of protons = number of electrons, on neutral elements

The Li element is an element located in group 1A

If we look at the atomic number of elements in group 1A:

• H: 1

• Li: 3

• Na: 11

• K: 19

• Rb: 37

• Cs: 55

• and Fr: 87

So Li has atomic number 3

Because atomic number = number of protons = number of electrons, so the number of protons from the element Lithium (Li) is<u> 3 </u>

 

<h3>Learn more </h3>

electron affinity

brainly.com/question/1440853

Identify the group number in the periodic table

brainly.com/question/2014634

the charge on each ion in the compounds

brainly.com/question/5880856

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Answer:

6.575

Explanation:

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2 years ago
A physics professor did daredevil stunts in his spare time. His last stunt was an attempt to jump across a river on a motorcycle
tatiyna

Answer:

a) 17.8 m/s

b) 28.3 m

Explanation:

Given:

angle A = 53.0°

sinA = 0.8

cosA = 0.6

width of the river,d = 40.0 m,

the far bank was 15.0 m lower than the top of the ramp h = 15.0 m,

The river itself was 100 m below the ramp H = 100 m,

(a) find speed v

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-h= vsinA\times t-gt^2/2

putting values h=15 m, v=0.8

-15 = 0.8vt - 4.9t^2  ............. (1)

horizontal displacement d = vcosA×t = 0.6×v ×t

so v×t = d/0.6 = 40/0.6

plug it into (1) and get

-15 = 0.8\times40/0.6 - 4.9t^2

solving for t we get

t = 3.734 s

also, v = (40/0.6)/t = 40/(0.6×3.734) =  17.8 m/s

(b) If his speed was only half the value found in (a), where did he land?

v = 17.8/2 = 8.9 m/s

vertical displacement = -H =v sinA t - gt^2/2

⇒ 4.9t^2 - 8.9\times0.8t - 100 = 0

t = 5.30 s

then

d =v×cosA×t = 8.9×0.6×5.30= 28.3 m

3 0
3 years ago
A force, F1, of magnitude 2.0 N and directed due east is exerted on an object. A second force exerted on the object is F2 = 2.0
IgorLugansk [536]

Answer:

Magnitude of the force is

F_3 = 2.83

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\theta = 45 degree West of South

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As we know that force is a vector quantity and in order to find the resultant of two or more forces we need to add them vectorialy

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direction of the force is given as

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3 0
3 years ago
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