Billy is paid $100 for 25 hours of work. What is his hourly rate?

Graph △XYZ with vertices X(2, 3), Y(−3, 2), and Z(−4,−3) and its image after the translation (x, y)→(x+3, y−1)

viktelen [127]

Answer:

X'(5, 2)
Y'(0, 1)
Z'(-1, -4)

Step-by-step explanation:

The translation increases each x-coordinate by 3, moving the point 3 units to the right. It decreases each y-coordinate by 1, moving the point 1 unit down.

(x, y) ⇒ (x+3, y-1)

X(2, 3) ⇒ X'(5, 2)

Y(-3, 2) ⇒ Y'(0, 1)

Z(-4, -3) ⇒ Z'(-1, -4)

The red arrows show the translation of each point in the graph.

5 0

4 years ago

(f/g)(x)and (f/g)(7)

Phoenix [80]

Answer:

$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}$

Step-by-step explanation:

Division operation of function: $If\ f(x)\ and\ g(x)\ are\ two\ functions\ then\ (\frac{f}{g})(x)=\frac{f(x)}{g(x)}$

$Here\ we\ have\ to\ find\ (\frac{f}{g})(7)\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}$

Example:

$Take\ f(x)=3x^2+1,\ g(x)=x+1\\\\(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(x)=\frac{3x^2+1}{x+1}\\\\f(7)=3\times 7^2+1\\\\f(7)=3\times 49+1\\\\f(7)=148\\\\g(7)=7+1\\\\g(7)=8\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}\\\\(\frac{f}{g})(x)=\frac{148}{8}$

7 0

3 years ago

What would be 12% of 40

weeeeeb [17]

Hello,

Answer:

4,8

Step-by-step explanation:

<u>what would be 12% of 40 ? </u>

12% × 40 = 12/100 × 40 = 0,12 × 40 = 4,8

3 0

2 years ago

The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using

Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

68.27% of the data lies within one standard deviation of the mean.

95.45% of the data lies within two standard deviations of the mean.

99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0

2 years ago

100+100÷100-100=10 prove it

Volgvan

Answer:

Step-by-step explanation:

100 + 100÷100 - 100 = 100 + 1 -100 {apply BODMAS}

= 101 - 100 = 1

7 0

3 years ago

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