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vesna_86 [32]
4 years ago
11

Solve -r/4 < 8         A.r<-32 B. r. >-32 C.r < -2D.r>-2

Mathematics
1 answer:
Gnom [1K]4 years ago
4 0
\frac{-r}{4}

Ans.\ B


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pickupchik [31]

Answer:

We conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

Step-by-step explanation:

<u>The complete question is</u>: A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored lowering environmental standards so that high-sulfur coal could be burned in coal-fired power plants. The results were:

Number sampled: 1,000 (republican) , 800 (democrats)

Number in favor: 200 (republican) , 168 (democrats)

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Let p_1 = <u><em>proportion of Republicans in favor of lowering the standards</em></u>.

p_2 = <u><em>proportion of Democrats in favor of lowering the standards</em></u>.

SO, Null Hypothesis, H_0 : p_1 \geq p_2     {means that there is an equal or larger proportion of Republicans in favor of lowering the standards}

Alternate Hypothesis, H_A : p_1 < p_2     {means that there is a larger proportion of Democrats in favor of lowering the standards}

The test statistics that would be used here <u>Two-sample z-test for</u> <u>proportions</u>;

                         T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of Republicans in favor of lowering the standards = \frac{200}{1000} = 0.20

\hat p_2 = sample proportion of Democrats in favor of lowering the standards = \frac{168}{800} = 0.21

n_1 = sample of Republicans = 1000

n_2 = sample of Democrats = 800

So, <u><em>the test statistics</em></u>  =  \frac{(0.20-0.21)-(0)}{\sqrt{\frac{0.20(1-0.20)}{1000}+\frac{0.21(1-0.21)}{800} } }

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The value of z test statistics is -0.52.

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Therefore, we conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

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