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vesna_86 [32]
3 years ago
11

Solve -r/4 < 8         A.r<-32 B. r. >-32 C.r < -2D.r>-2

Mathematics
1 answer:
Gnom [1K]3 years ago
4 0
\frac{-r}{4}

Ans.\ B


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Answer: 20 cups

Step-by-step explanation:

(1/3 × 20) × 3 = 20 cups

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Makovka662 [10]
Solve for x:x/5 - 2 = x/2 + 3
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x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer:  x = (-50)/3
7 0
2 years ago
60 pOINTS HELP PLEASE 4. A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5
Solnce55 [7]
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
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gpe = 20 \times 9.81 \times 2 \\ gpe = 40 \times 9.81 \\ gpe = 392.4 \: joules
g is taken as 9.81
6 0
3 years ago
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