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aksik [14]
3 years ago
7

Solve my math problem

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0
What is the math problem??
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Point A(12, 0) is on the x-axis and point B(0,−5) is on the y-axis. Find the distance between points A and B
Delvig [45]
The distance is 12/-5
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What is the probability that a randomly selected person is on the swim team? Express the probability as a percent rounded to the
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28 out of 67 people are on the swim team
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Goryan [66]

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2. the figure has rotatinal symetry

Step-by-step explanation:

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3 years ago
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The back of jake's property is a creek. Jake would like to enclose a rectangular area, using the creek as one side and fencing f
kow [346]

Answer:

The maximum possible area of the pasture  is 26,450 feet square.

Step-by-step explanation:

Let us assume the width of the rectangular area  = m  ft

and the length of the area = k ft

Also assume:  ( one side with k units IS NOT FENCED)

So, the total  perimeter of the fencing is:

2 m + k = 460

or, k = 460 - 2m  ........ (1)

Now, AREA OF THE RECTANGULAR PORTION = Length x  Width  = k x m

Put  k =  460 - 2m

We get:   A = m (460 - 2m)

or, A =  460 m  - 2m²

We need to find the maximum for the parabolic function A = 460 m  - 2m²

The function has a maximum value as the quotient in front of x^2 is negative: -2 < 0

A (max)  = c-\frac{b^2}{4a}   where a = -2, b = 460, c = 0

= -\frac{(460)^2}{4(-2)}  = 26,450

A max = 26,450 sq ft.

The maximum possible area of the pasture  is 26,450 feet square.

7 0
3 years ago
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