If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
Answer:
150.08 inches
Step-by-step explanation:
The question simply requires that we find the length of the arc that the dog walks.
Its leash rotates through 150° and the length of the leash (radius) is 60 inches.
The length of an arc is given as:
L = α/360 * 2πR
where α = angle of arc
R =radius
Therefore:
L = 150/360 * 2 * π * 60
L = 150.08 inches
The dog walks 150.08 inches
Answer:
Already stole herrrrrr ahahah
Step-by-step explanation:
