All categories

2 years ago

Find the total surface area of this cylinder.

Mathematics

1 answer:

Mkey [24]2 years ago

5 0

Answer:

sorry I didn't know mark as btaiblist

You might be interested in

3. the answer isn't c or d

Kay [80]

Answer:

A. Yes; no vertical line passes through two graphed points

Step-by-step explanation:

3 0

2 years ago

A recipe needs 5/4 of a cup of sugar you are going to triple the recipe how much sugar do you need?

Schach [20]

The answer is 16/2 cups of sugar

8 0

4 years ago

Read 2 more answers

HEEELLLPPP!!!!!!!!! PLEEAASEEE!!!!!!!!

Ksivusya [100]

Answer:

Step-by-step explanation:

$17. (a^{m})^{n}=a^{m*n}\\\\a^{m}*a^{n}=a^{m+n}\\\\-3k^{2}*(4k^{5})^{3}=-3k^{2}*4^{3}*k^{5*3}\\\\ = -3k^{2}*64*k^{15}\\\\= (-3)*64*k^{2+15}\\\\= - 192k^{17}$

$19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\$

$20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}$

4 0

2 years ago

A stocker put 57 boxes of detergent on the shelves in 2 minutes. After 5 minutes, he had put 117 boxes on the shelves. How many

erastovalidia [21]

57 boxes of detergent on the shelves in 2 minutes
After 5 minutes, he had put 117 boxes on the shelves

117 - 57 = 60 (60 boxes of detergent for 3 minutes)
60/3 = 20 (20 boxes of detergent per minute)
so

20 x 5 = 100 boxes of detergent

117 - 100 = 17 boxes

answer
17 boxes of detergent were on the shelves when he started

7 0

3 years ago

Read 2 more answers

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.

In other words, the domain is $(-\infty, 7) \cup (7, \infty)$ .

5 0

3 years ago