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Elan Coil [88]
3 years ago
8

Which answer shows y + 2x< 4x - 3, rewritten to isolate y, and its graph?

Mathematics
1 answer:
leonid [27]3 years ago
7 0

Answer:

y<2x−3 would be the answer

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Identify the properties of equality needed to isolate a varaible and solve a given equation. Use the drop-down menus to show you
Anna71 [15]

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If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. When you solve an equation, you find the value of the variable that makes the equation true. In order to solve the equation, you isolate the variable.

4 0
3 years ago
What model describes the relationship between the amount of money in an account and time, given that the money doubles every mon
quester [9]
If we have a common ratio every set amount of time (and not a common difference or addition), this is an exponential relationship. An exponential equation would have a form like Money = (1000)(2)^(# of months), where every additional month would cause the money amount to double.
3 0
4 years ago
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Determine whether each statement is True or False.<br>Answer ASAPPP plz i need your help
Gennadij [26K]

Answer:

Step-by-step explanation:

The closest to sea level is - 11. The minus sign indicates that you are below 0 or the level of the sea at that location. So what is true and what isn't?

Grasshopper meadow is not closest to sea level. At 15 feet it is 4 feet more above the closest one at - 11. False

Echo point is the highest above sea level. It is 45 feet above sea level. This statement is also False.

3 0
3 years ago
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
What's the Sin 39 degrees?
yanalaym [24]
<span>Value of Sin(39 degree) = 0.62932039

hope that helps</span>
7 0
3 years ago
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