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2 years ago

Help me plz help me plz ??

Mathematics

2 answers:

Oduvanchick [21]2 years ago

7 0

Answer:

I just want points hahahaha

hram777 [196]2 years ago

6 0

Y=2X+7 because you’re adding 2 to every section. I hope this helps you unlike that other guy who answered the question just for points.

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Will a 11.5-inch x 18-inch rectangular tray fit in<br> the box shown? Explain.

pychu [463]

Answer:

Option D

Step-by-step explanation:

From the picture attached,

In the parallelogram ABCD,

Length of diagonals AC and BD are equal.

By the property,

"If the lengths of the diagonals of a parallelogram are equal, parallelogram will be a rectangle".

Therefore ABCD is a rectangle.

That means all interior angles of the given rectangle will be 90°.

Now we apply Pythagoras theorem in right triangle ΔABC,

AC² = AB² + BC²

(22)² = (12)² + (BC)²

484 - 144 = (BC)²

BC = √340

BC = 18.44 inches

Dimensions of the given box are 12 inches by 18.44 inches.

Dimensions of the rectangular tray is 11.5 inches by 18 inches.

Since, dimensions of the box are larger than the dimensions of the tray, tray can be adjusted in the box.

Therefore, Option D will be the answer.

3 0

2 years ago

The Varners live on a corner lot. Often children cut across their lot to scar walking distance. The diagram to the right represe

icang [17]

About 12.56 units.
Solve for x by plugging in values into Pythagorean theorem.
$a^{2} +b^{2} = c^{2}$
$x^{2} +(x+12)^{2} = 34^{2}$
Simplify
$2x^{2} + 24x+144 = 1156$
Subtract 144 from both sides
$2x^{2} + 24x = 1012$
divide both sides by 2
$x^{2} + 12x = 506$
complete the square
$x^{2} + 12x + 36 = 506 +36 . = (x+6)^2 = 542$
take the square root of both sides.
$x+6 = 23.28$
subtract by 6 to get about 17.28 for x.
Plug in values for x to get distance traveled on outside of the yard.
17.28 + (17.28 +12) = 46.56
subtract 34 from the length to get the difference in travel. 46.56-34=12.56

8 0

3 years ago

Find the area of a parallelogram bounded by the y-axis, the line x = 3, the line f (x) = 1 + 2x, and the line parallel to f (x)

ExtremeBDS [4]

There is not enough info ( ͡° ͜ʖ ͡°)

5 0

3 years ago

Find the tenth term of the geometric sequence, given the first term and common ratio.

Natalija [7]

Answer:

$a_{10}=\dfrac{1}{128}$

Step-by-step explanation:

In the geometric series:

$a_1=4\\ \\r=\dfrac{1}{2}$

The nth term of the geometric sequence can be calculated using formula

$a_n=a_1\cdot r^{n-1}$

In your case, n = 10, then

$a_{10}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^{10-1}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^9\\ \\=2^2\cdot \dfrac{1}{2^9}\\ \\=\dfrac{1}{2^{9-2}}\\ \\=\dfrac{1}{2^7}\\ \\=\dfrac{1}{128}$

8 0

2 years ago

Could 13 15 and 19 be a right triangle

Nat2105 [25]

Answer:

No b/c the hypotenuse is too short

Step-by-step explanation:

13² + 15² = 19²

169 + 225 = 361

394 ≠ 361

6 0

3 years ago