I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
100 is the answer (100x 2 = 200)
X-4y=-12
4x-y=12
eliminate y's
multily 2nd equaiton by -4 and add to top one
x-4y=-12
<u>-16x+4y=-48 +
</u>-15x+0y=-60
-15x=-60
divide both sides by -15
x=4
sub back
x-4y=-12
4-4y=-12
minus 4 both sides
-4y=-16
divide both sides by -4
y=4
x=4
y=4
(x,y)
(4,4)<u>
</u>
you start at the origin and go down 4 right 1. So the range is 4 and the domain is x
Step-by-step explanation:
Answer: …
Step-by-step explanation: you need an image