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zloy xaker [14]
3 years ago
8

MATH QUESTION I NEED HELP!!!!

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0

Answer: B) 0 ≤ y < infinity

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Here please helppppppppppppp
skelet666 [1.2K]

Answer:

  • Part 2 - ∠EGF = 105°
  • Part 3 - ∠D = 65
<h3>________________________________________________</h3>

Step-by-step explanation for Part-2:

<u>We know that:</u>

  • ∠EFG = 32°
  • ∠AEG = 137°
  • ∠EFG + ∠FGE + ∠GEF = 180°

<u>Work:</u>

  • ∠EFG + ∠FGE + ∠GEF = 180°
  • 32 + ∠FGE + (180 - 137) = 180°
  • => 32 + ∠FGE + 43 = 180°
  • => 75 + ∠FGE = 180°
  • => ∠FGE = 180 - 75
  • => ∠FGE = ∠EGF = 105°

Hence, the measure of ∠EGF is 105°.

<h3>________________________________________________</h3>

Step-by-step explanation for Part-3:

<u>We know that:</u>

  • CD = CA
  • This triangle is an isosceles triangle.
  • ∠D = ∠A

<u>Work:</u>

  • 50 + ∠D + ∠A = 180
  • => ∠D + ∠D = 130
  • => 2∠D = 130
  • => ∠D = 130/2
  • => ∠D = 65

Hence, the measure of ∠D is 65°

<h3>________________________________________________</h3>
7 0
2 years ago
Which of the following would be equivalent to 9 to the power of 2 ⋅ 9 to the power of 6?
Anna35 [415]
9^{2} * 9^{6} =  9^{2+6} = 9^{8} = 43046721
7 0
4 years ago
Define the words <br><br> please help
Brrunno [24]

Answer:

Irrational Number: A number that cannot be written as a fraction  

a

b

(where b ≠ 0), a repeating decimal, or a terminating decimal.

Rational Number: A number that can be written as a fraction  

a

b

(where b ≠ 0), a repeating decimal, or a terminating decimal.

Repeating Decimal: A decimal where, when dividing, a digit or group of digits repeats without end in the quotient; there is a pattern in the digits that repeat without end.

Terminating Decimal: A decimal that, when dividing, ends with a remainder of zero.

Perfect cube: A number that is made by cubing a number: a3 = a • a • a.

Perfect square: A number that is made by squaring a number: a2 = a • a.

Cube Root:

if a3 = b, then a = 3√b

For principal square root this was the best I could do: The principle of square roots requires that the square root of the side with the unknown (x) only includes x without any exponent (other than 1). The simplest form that fits this criterion is: but x can also be an expression.

I hope this helps :3

6 0
3 years ago
Read 2 more answers
Please help with my math problem
REY [17]
Answer is B hope it helps
6 0
4 years ago
Solve for x squared - 12x+59=0
dalvyx [7]
We solve the equation x^2 - 12x + 59 = 0

First we use x^2 - 12x + \displaystyle\sum_{n=1}^{\sum_{i=5}^6i}\left(\frac{59}{11}\right) in order to compute our answer and then we use Justin Bieber's <span><em>I close my eyes and I can see a better day</em> </span> Theorem that says that

The\ solutions\ to\ x^2 - 12x + \displaystyle\sum_{n=1}^{\sum_{i=5}^6(i)}= 0 \\ \\ \\ \ are\ x=6+\sqrt{23}i,\:x=6-\sqrt{23}i

Here is a proof of Justin Bieber's <span>I close my eyes and I can see a better day T</span>heorem which uses the advanced techniques of mathematicians:

x^2 - 12x + \displaystyle\sum_{n=1}^{\sum_{i=5}^6(i)}= 0 \\  &#10;x^2 - 12x + 59 = 0\\ &#10;\implies x = \frac{-(-12) \pm \sqrt{(-12)^2 - 4(1)(59)} }{2(1)} \\ &#10;x = \frac{12 \pm \sqrt{144 - 236} }{2} \\&#10;x =  \frac{12 \pm \sqrt{-92} }{2}  \\&#10;x =  \frac{12 \pm 2\sqrt{-23} }{2}  \\&#10;x = 6 \pm 2 \sqrt{23} i  \\

6 0
4 years ago
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