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2 years ago

Here please helppppppppppppp

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

7 0

Answer:

Part 2 - ∠EGF = 105°
Part 3 - ∠D = 65

Step-by-step explanation for Part-2:

∠EFG = 32°
∠AEG = 137°
∠EFG + ∠FGE + ∠GEF = 180°

∠EFG + ∠FGE + ∠GEF = 180°
32 + ∠FGE + (180 - 137) = 180°
=> 32 + ∠FGE + 43 = 180°
=> 75 + ∠FGE = 180°
=> ∠FGE = 180 - 75
=> ∠FGE = ∠EGF = 105°

Hence, the measure of ∠EGF is 105°.

Step-by-step explanation for Part-3:

CD = CA
This triangle is an isosceles triangle.
∠D = ∠A

50 + ∠D + ∠A = 180
=> ∠D + ∠D = 130
=> 2∠D = 130
=> ∠D = 130/2
=> ∠D = 65

Hence, the measure of ∠D is 65°

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3 years ago

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3 years ago

A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9, and the sample stand

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Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

$H_0:\mu=100$ and $H_1:\mu \:>\:100$ (claim)

<u>Step 2</u>: Calculate the test value.

$t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$

$\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263$

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

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3 years ago

If you deposit $12,500 in an account that pays 4.5% interest quarterly, what is the balance after 8 years? How much did the acco

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$A=P(1+\frac{r}{n})^{nt}$

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Replace the previous values of the parameters into the formula for A and simplify:

$\begin{gathered} A=12,500(1+\frac{0.045}{4})^{4\cdot8} \\ A=12,500(1+0.01125)^{32} \\ A=12,500(1.01125)^{32} \\ A=12,500(1.430451402) \\ A\approx17,880.64 \end{gathered}$

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