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2 years ago

Solve the system of equations algebraically. Show all of your work. y= x^2 + 2x y= 3x +30

Mathematics

1 answer:

QveST [7]2 years ago

4 0

Answer:

See attached below

Step-by-step explanation:

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Plzz solve this easy calculus :')

Digiron [165]

Answer:

$\sin \: x - \cos x \: + c$

Step-by-step explanation:

$\int \frac{cos2x}{ \sqrt{1 - sin2x} } dx \\ \\ = \int \frac{ {cos}^{2}x - {sin}^{2}x } { \sqrt{ {sin}^{2}x + {cos}^{2}x - 2sinx \: cosx } } dx \\ \\ = \int \frac{ ({cos}x - {sin}x )({cos}x + {sin}x )} { \sqrt{ {({cos}x - {sin}x )}^{2} } } dx \\ \\ = \int \frac{ ({cos}x - {sin}x )({cos}x + {sin}x )} {{ {({cos}x - {sin}x )} } } dx \\ \\ = \int({cos}x + {sin}x)dx \\ \\ = \int{cos}x \: dx + \int{sin}x \: dx \\ \\ = \sin \: x - \cos x \: + c$

3 0

2 years ago

May you please answer this question i tried to answer but failed miserably

s2008m [1.1K]

Answer:

I think it is postive

7 0

2 years ago

Hellp me solve this thanks

stellarik [79]

Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

$area(a) = 105 {cm}^{2}$

the perpendicular distance means the height so lets find the height

area of trapizium= B1 + B2 × h

2

${105cm}^{2}(the \: given \: area) = \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2} \times h$

${105cm}^{2} = \frac{21cm}{2} \times h$

now we crisscross

${105cm}^{2} \times 2 = 21cm \times h$

${210cm}^{2} = 21cm \times h$

$\frac{ {210cm}^{2} }{21cm} = \frac{21cm \: }{21cm} \times h$

h = 10 cm

hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

4 0

2 years ago

How many solutions are there in this equation 8 (x-3)=8x-24

kari74 [83]

Performing the indicated multiplication on the left side gives you:

8x-24=8x-24,

8x=8x

1=1

These expressions are true for any real value of x and thus has infinitely many solutions...

3 0

2 years ago

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What is the answer to 2(x-3)-4(x+3)

Lyrx [107]

Step-by-step explanation:

2 (x-3)-4 (x+3)

2x-6-4x-12
-2x-18
-2(x+9)

7 0

2 years ago

Read 2 more answers