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STatiana [176]
3 years ago
15

In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th

e final exam. There are 100 points available for each score. However, the lab score is worth 23% of your total grade, each major test is worth 21.5%, and the final exam is worth 34%. Compute the weighted average for the following scores: 67 on the lab, 69 on the first major test, 85 on the second major test, and 63 on the final exam.
Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer:

The weighted average is of 69.94.

Step-by-step explanation:

Weighted average:

The weighed average is found multiplying each grade by its respective weight.

The grades, and weights are:

67 on the lab, with a weight of 23% = 0.23

69 on the first major test, with a weight is 21.5% = 0.215

85 on the second major test, with a weight is 21.5% = 0.215.

63 on the final exam, with a weight of 34% = 0.34.

Weighted average:

A = 0.23*67 + 0.215*69 + 0.215*85 + 0.34*63 = 69.94

The weighted average is of 69.94.

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 12, b = 14
Eva8 [605]
We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12  A=56°
b=14  B=75.3°
c=10.9  C=48.7°

case 2) 
A=56°
a=12
b=14
B=180-75.3----> B=104.7°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12  A=56°
b=14  B=104.7°
c=4.8    C=19.3°
3 0
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