A) condensation
B) the air around the glass of ice water is cooled. Moisture in the air condenses out once the temperature of the air reaches below the dew point.
C) evaporation
D) as the water is left out the warm temperatures allows the water to evaporate over time.
Answer:
<em>No</em>, a pentagon can NOT be a cross-section of a triangular prism.
Step-by-step explanation:
Prisms have a uniform cross-section and are named after their cross-section. Hence, the cross section of a triangular prism is a triangle. The only prism with a pentagon cross-section is a pentagonal prism.
Answer: 9−27
Step-by-step explanation:
Answer:
Blue
Step-by-step explanation:
First, we need to find the LCD (Least common denominator)
Rewriting input as fractions if necessary:
1/10, 1/4, 1/5
For the denominators (10, 4, 5) the least common multiple (LCM) is 20.
Therefore, the least common denominator (LCD) is 20.
Now, we convert:
Red Marbles: 1/10 = 2/20
Blue Marbles: 1/4 = 5/20
Yellow Marbles: 1/5 = 4/20
As we can see, blue has the most. Now we have our answer! Good luck!
Answer:
Eq: (x+a/2)²+(y+1)²=(a²-8)/4
Center: O(-a/2, -1)
Radius: r=0.5×sqrt(a²-8)
Mandatory: a>2×sqrt(2)
Step-by-step explanation:
The circle with center in O(xo,yo) and radius r has the equation:
(x-xo)²+(y-yo)²=r²
We have:
x²+y²+ax+2y+3=0
But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4
And
y²+2y+3=y²+2y+1+2=(y+1)²+2
Replacing, we get:
(x+a/2)²-a²/4+(y+1)²+2=0
(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4
By visual inspection we note that:
- center of circle: O(-a/2, -1)
- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)