Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
0+4+(-16)=-12
I think the answer is 9.3, but I’m not sure
Answer:
The answer to this question is 49+2m.
Answer:
y=2, x=-1
Step-by-step explanation:
We can add the two equations together to eliminate x:
6x+5y+(-6x)+7y=4+20
12y=24
y=2
We plug y into the first equation and get
6x+5(2)=4
6x+10=4
6x=-6
x=-1