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2 years ago

Write TRUE if the underlined word in the statement is correct.If not , change the underlined word to make it correct.

Mathematics

1 answer:

kobusy [5.1K]2 years ago

7 0

Change the underlined words if it is not correct and write true if it is correct.

<h3>Integers</h3>

1. Positive integers are not whole numbers.

Negative integers are not whole numbers.

2. All whole numbers are integers.

True

3. Zero is the smallest whole number.

True

4. Any whole number greater than zero is a positive integers.

True

5. Fractions and Decimals are not integer.

6. 1 is a counting number and a positive integers.

True

7. Rational number include all integers , fraction, or terminating decimals.

True

8. Any whole number that is greater than 0 is a negative integers.

Any whole number that is less than 0 is a negative integers.

Learn more about integers:

brainly.com/question/10853762

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Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

2 years ago

Solve for x 3x + 10 - 4 = 21

Ivan

Answer:

X = 5

Step-by-step explanation:

6 0

3 years ago

8. The height of a ball t seconds after

Nina [5.8K]

Answer:

B) 16

Step-by-step explanation:

We have h(t)=0, because the ball is on the ground.

So we have:

-8(2t-32)=0

2t-32=0

2t=32

t=16

It took 16 sec

4 0

2 years ago

Taseem’s loose change consists of dimes and quarters. When you ask her how many of each type of coin she has, she gives you the

sweet-ann [11.9K]

The statement first, and the statement second are correct because the number of dimes is 34, and the number of quarters is 66

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

0.1x + 0.25y = 19.9 and

x + y = 100

Let x = number of dimes

y = number of quarters

After solving the above system of equations by substitution method.

$\rm \dfrac{398-5y}{2}+y=100$

y = 66

$\rm x=\dfrac{398-5\cdot \:66}{2}$

x = 34

Thus, the statement first, and the statement second are correct because the number of dimes is 34, and the number of quarters is 66

Learn more about the linear equation here:

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4 0

1 year ago

Select the two values of x that are roots of this equation. 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

8 0

2 years ago