Not sure but probably it’s b or c
Answer in fraction form is 1/3
Answer in decimal form is 0.3333
Pick one answer only.
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Explanation:
The sample space is the set of all possible outcomes. In this case, the outcomes consist of values between 1 and 6
S = sample space
S = {1,2,3,4,5,6}
There are 6 items here. Let B = 6.
We want to roll a number greater than 4, so the event space we're after is
E = {5,6}
which consists of 2 items. Let A = 2.
The probability we want is A/B = 2/6 = 1/3 = 0.3333
So if you go with the fraction option, then you'll type in 1/3
If you go with the decimal option, then you'll type in 0.3333
Answer:
A=8.75 in.
Step-by-step explanation:
Since ∆ HBA & ∆HKJ are similar,
HB/HA = HK/HJ
3/5.25 = 8/HJ
3HJ/5.25 = 8
3HJ = 42
HJ = 14 in.
AJ = 14 - 5.25
AJ = 8.75 in.
Therefore
A=8.75 in.
I hope this helped you.
Answer:

Step-by-step explanation:
In order to find the equation to this line, we need to note that we see two points on this graph. Using these two points, we can use them to find the slope of the graph and use one to find the y-intercept.
We know that the slope of a line is defined by
(change in y / change in x). Therefore, we can use our two points that we know - (-5, 2) and (3, 4) to find the slope.
The change in y is
, and the change in x is
. Therefore, our slope is
.
Now that we know our slope, our equation in slope-intercept form looks something like this.

However, we still have b to solve for. We can solve for this by substituting a point we already know into the equation. Let's substitute (3, 4) inside.
So now we know that the y-intercept is
. Plugging that into our equation finishes it off, leaving our final equation to be
.
Hope this helped!
Answer:
1/6; 1/2; 1/12; P(T|3) = 1/2; therefore, events are independent because P(T|3) = P(T).
Step-by-step explanation:
The probability of rolling a 3 on a six-sided die is 1/6. This is because there is one 3 out of 6 possibilities.
The probability of flipping a coin on tails is 1/2. This is because there is one side "tails" out of 2 possibilities.
The probability of rolling a 3 and flipping tails is 1/6(1/2) = 1/12.
P(T|3) = P(3 and Tails)/P(3) = 1/12 / (1/6) = 1/12(6/1) = 6/12 = 1/2
Since P(T|3) = P(3), these are independent events.