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3 years ago

Find the Volume of the shape below. V = yd³

Mathematics

1 answer:

Ganezh [65]3 years ago

3 0

Answer:

$v = \frac{b \times h \times l}{2} \\ \frac{12 \times 6 \times 14}{2} \\ = 504$

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if a lady chargers $2.00 for gas and $3.00 per 1/2 hour of work . What is the amount of money she makes in 4 hours ?

anastassius [24]

Answer:

$32

Step-by-step explanation:

The lady charges $2.00 for gas which means over a 4 hour period we would do

4 x 2 = 8

She makes a total of 8 dollars

She also gains $3.00 per half hour of work

This means we would do 3 x 8

We add these values to get $32

4 0

3 years ago

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Please check 1 and 2 and help with 3 and 4

Sindrei [870]

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2 years ago

Need help will give you the brainliest

natali 33 [55]

Answer:

164,160 just do 96% of it

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3 years ago

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What is the answer to 2(12-18x)=x-11x

Ivan

Answer:

x=0

Step-by-step explanation:

move all terms to the left. Then add all the numbers together. Then multiply parenthesis to get rid of them finally add all numbers together

4 0

3 years ago

The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

Thus solutions of "h" are:

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0

3 years ago