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3 years ago

HELP ME OUT! Triangle ABC is transformed by a rotation about the

Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

Answer : 180 degrees

2 units left

5 units down

Your welcome ❤️

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Two legs of a right triangle are 4cm, and 3cm. find the length of the hypotenuse of this triangle

sergiy2304 [10]

It'll be 4^2+ 3^2 then the answer you get you take the square root of it which will give you the hypotenuse.
Your answer would be 5 because square root of 25 is 5
If u want the formula it's a^2+b^=c^2
C is the hypotenuse and a and b is the lengths

6 0

4 years ago

Simplify: (–2x+y)(-58 y)<br> O 10x10,<br> 10xv2<br> 10xy<br> 10x10 ,

alekssr [168]

Answer:

Choice C

Step-by-step explanation:

$(-2x^2y)(-5x^5y^3)=\\\\(-2)(-5)\times (x^2)(x^5)\times (y)(y^3)=\\\\10x^7y^4$

Hope this helps!

8 0

3 years ago

A random experiment consists of tossing 2 coins and observing heads and tails. What is the correct sample space

AVprozaik [17]

This is

{HH, TT, TH, HT} where H = head and T = tail

6 0

4 years ago

Jessica pours 1/3 of a cup of water into a pot. She does this 5 times. How many

nydimaria [60]

She poured 1 full cup and 2/3 of another cup. The answer would be 1 and 2/3 cups.

5/3= 1 and 2/3

4 0

3 years ago

Get the general term for the sequence being your t3 = 11 and the t20 = 244.2

marusya05 [52]

Answer:

nth term = $t_{n} = 7.639(1.2)^{n - 1}$

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = $t_{3} = ar^{2} = 11$ .......... (1) and

20th term = $t_{20} = ar^{19} = 244.2$ ........... (2)

Now, dividing equation (2) with equation (1) we get

$\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2$

⇒ $r^{17} = 22.2$

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = $t_{n} = 7.639(1.2)^{n - 1}$ (Answer)

5 0

3 years ago