Answer:
We accept H₀ , we do not have enought evidence for rejecting H₀
Step-by-step explanation:
Normal Distribution
sample size n = 60
standard deviation σ = 15
1.Hypothesis Test : Is a one tailed-test on the right
H₀ null hypothesis μ₀ = 50
Hₐ alternative hypothesis μ₀ > 50
2.-We will do the test for a significance level α = 0,01 tht means for a 99% interval of confidence
then z(c) = 2.32
3.- We compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n ) ⇒ z(s) = ( 2 * √60 ) / 15
z(s) = 15.49/15 ⇒ z(s) = 1.033
4.- We compare values of z(c) and z(s)
z(s) < z(c) 1.033 < 2.32
z(s) is in the acceptance region so we accept H₀ , we do not have enough evidence for rejecting H₀
Time is 4 hrs., coffee is 0 cups. Point (4,0)
So A
Just finished this for another student.
Length = 9
Answer:
So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.
Absorbance is the inverse of transmittance so,
A = 1/T
Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:
A ∝ b · c
As Transmittance, 
% Transmittance, 
Absorbance,
Hence, 
is the algebraic relation between absorbance and transmittance.
Answer:
If the four number sentences at the bottom are the choices for your answer the correct one would be choice A or 1.
I hope this is what you meant if not I'll try to take my answer down and try to answer it again correctly!
