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DaniilM [7]
3 years ago
5

Help please

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

B) Y - 3= -1/7 ( x - 3 )

Step-by-step explanation:

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What are the Six steps of statistical investigation ?
dimaraw [331]
Step 1ask a research questionstep 2design a study and collect datastep 3explore the datastep 4draw inferences beyond the datastep 5formulate conclusionsstep 6<span>look back and ahead</span>
5 0
4 years ago
Find all the powers of 4 in the range 4 through 1000
marissa [1.9K]
Powers of 4 are like 4^1, 4^2, 4^3 and so on
remember that 4^x means 4 times itself x times for example
4^3=4 times iteslef 3 times=4 times 4 times 4

so the multipules of the powers of 4 are just 4 times of the previous
so we will list

4^1=4
4^2=16
4^3=64
4^4=256
4^5=1024

1024 is already more than 1000 so the list stops and is
1,16,64,256
8 0
3 years ago
Someone please help me?
kirza4 [7]

Answer:

jus press alt f4 and a overlay will open up with all the answers

Step-by-step explanation:

7 0
3 years ago
Thirty-seven percent of all Americans drink bottled water more than once a week (Natural resources Defense Council, December 4,
lesantik [10]

Answer:

a) The sampling distribution for n=540 has a mean sample proportion of p=0.37 and a standard deviation of σs=0.0208.

b) probability = 0.99998

d) probability = 0.99874

e) You gain 0.12% in probability for an increase of 80% in sample size.

The increase in sample size is not justified by the increase in probability, for this margin of error (Δp=0.09).

Step-by-step explanation:

a) We have a known population proportion π=0.37 and we have to describe the sampling distribution when the sample size is n=540.

The mean sample proportion is expected to be the same as the population proportion:

\bar p = \pi = 0.37

The standard deviation of the sampling will be the population standard deviation divided by the square root of the sample size:

\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.37*0.63}{540}}=\sqrt{0.000431667}=0.0208

Then, we can say that the sampling distribution will have a p=0.37 and a standard deviation σs=0.0208.

b) We have to calculate the probability that the sample proportion will be within 0.09 of the population proportion.

We can calculate the z-value as:

z_1=\dfrac{p_1-\bar p}{\sigma_s}=\dfrac{0.09}{0.0208}=4.3269\\\\\\z_2=\dfrac{p_2-\bar p}{\sigma_s}=\dfrac{-0.09}{0.0208}=-4.3269

As the distribution is symmetrical, we can calculate the probabilty that he sample proportion will be within 0.09 of the population proportion as:

P(|p-\bar p|

probability = 0.99998

d. Now the sample is smaller (n=300), so the standard deviation of the samping distribution:

\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.37*0.63}{300}}=\sqrt{0.000777}=0.0279

We have to recalculate the z-scores:

z_1=\dfrac{p_1-\bar p}{\sigma_s}=\dfrac{0.09}{0.0279}=3.2258\\\\\\z_2=\dfrac{p_2-\bar p}{\sigma_s}=\dfrac{-0.09}{0.0279}=-3.2258

And the probability is:

P(|p-\bar p|

probability = 0.99874

e. The increase in sample size is 80%

\Delta n\%=\dfrac{n_1}{n_2}-1=\dfrac{540}{300}-1=1.8-1=0.8=80\%

and the increase in probability is 0.12%

\Delta P\%=\dfrac{P_1}{P_2}-1=\dfrac{0.99998}{0.99874}-1=1.0012-1=0.0012=0.12\%

You gain 0.12% in probability for an increase of 80% in sample size.

The increase in sample size is not justified by the increase in probability, for this margin of error (Δp=0.09).

7 0
3 years ago
Suppose the matrix representing a system of difference equations contains a column of zeros. What does this imply about the syst
zhuklara [117]

Answer:

It is a singular matrix system.

Step-by-step explanation:

A column of all zeros in a matrices says that the variable associated with that column has no effect on the output.

For example If the first column of a matrix consists of zeros, this means that the coefficient of the first variable is zero in every equation in the system . This means that if there is any solution at all, then there must be an infinite number of them, since you can set that first variable to any value at all and still satisfy all of the equations.

5 0
4 years ago
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