Umm this should be in physics but F is proportional to 1/r^2 I am assuming you want to just take the derivative in respect to r of both sides of the equation
F = (2.99x10^16)/r^2
So you do that and you get
dF/dr = -2(2.99 * 10 ^16)/ (r^3)
is this for calc class?
Answer:
2 380m
Step-by-step explanation:
very simple just multiply 7×340
Answer:
−2 is a member of the domain of f.
f(0) > 0
Step-by-step explanation:
Statement 1 is TRUE. Domain value includes set of values of x of the function. -2 is plotted on the x-axis on the graph. Therefore, it is a member of domain of f.
Statement 2 is incorrect. Range includes all possible y-values of the function. On the graph, no y-value plotted is -2. Therefore, -2 is NOT a member of the range of f.
Statement 3 is TRUE.
f(0) is approximately 2.2 on the graph. i.e. at x = 0, y ≈ 2.2.
Therefore, f(0) > 0.
Statement 4 is INCORRECT.
f(2) = 1, that is at x = 2, y = 1 as seen in the graph. Therefore, f(2) is not greater than 2.
<span>y=−1/3x+1
</span>x = -6, y = −1/3(-6) +1 = 3<span>
x = -3, y = </span>−1/3(-3) +1 = 2<span>
x = 0, y = 1
</span>x = 3, y = −1/3(3) +1 = 0
x = 6, y = −1/3(6) +1 = -1
<span>
Table
x y
-6 3
-3 2
0 1
3 0
6 -1
</span>
Answer:
0.84
If you're looking for a percentage it'd be 84%
Step-by-step explanation:
