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3 years ago

5

Need help on this.. The first one that answer it first correctly gets a BRANLIST

2 answers:

Elena-2011 [213]3 years ago

7 0

Answer:

A i think

Step-by-step explanation:

dedylja [7]3 years ago

5 0

Answer: The answer is C) J' (3,-1), K' (1,-4)

Step-by-step explanation: First, you need to find the location of J, which is located in Quadrant III. You go left 3, and go down 1, making the coordinates of J (-3,-1). Next, you need to find the location of K, which is also located in (-1, -4).

So, the question asks, "What are the coordinates of J' and K' after JK is reflected across the y-axis?"-- Well, first, which line is the x-axis, and which line is the y-axis?

The x-axis is the line that is horizontal(Across) while the y-axis is the line that is vertical( Up and Down).

So you bring J and Ks coordinated over the y-axis to Quadrant IV(4). You already know their original coordinates, so you place the as you would in the picture above, except that the line would be reflected.

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Help my dear friend answer this:

fomenos

Subtract 21 from 1,176 to get the length

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3 years ago

Read 2 more answers

Vance is designing a garden in the shape of an isosceles triangle. The base of the garden is 30 feet long. The function y = 15 t

Sever21 [200]

Answer:

Part 1) The height of the triangle when θ = 30° is equal to $8.66\ ft$

Part 2) The height of the triangle when θ = 40° is equal to $12.59\ ft$

Part 3) The area of triangle with θ = 30° is less than the area of triangle with θ = 40°

Step-by-step explanation:

Part 1) What is the height of the triangle when θ = 30 ° ?

we have

$y=15tan(\theta)$

substitute the value of theta in the equation and find the height

$y=15tan(30\°)=8.66\ ft$

Part 2) What is the height of the triangle when θ = 40 ° ?

we have

$y=15tan(\theta)$

substitute the value of theta in the equation and find the height

$y=15tan(40\°)=12.59\ ft$

Part 2) Vance is considering using either θ = 30 ° or θ = 40 ° for his garden

Compare the areas of the two possible gardens

step 1

Find the area when θ = 30 °

The height is $8.66\ ft$

Remember that the area of a triangle is equal to the base multiplied by the height and divided by two

so

$A=(1/2)(30)(8.66)=129.9\ ft^{2}$

step 2

Find the area when θ = 40°

The height is $12.59\ ft$

Remember that the area of a triangle is equal to the base multiplied by the height and divided by two

so

$A=(1/2)(30)(12.59)=188.85\ ft^{2}$

Compare the areas of the two possible gardens

The area of triangle with θ = 30° is less than the area of triangle with θ = 40°

7 0

2 years ago

Complete the proof in picture

BARSIC [14]

it won't let me type the answer I may be missing something but it says I am using rude words so sorry if I am

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3 years ago

Shipping department 17 employees budget of 3715 budget

Masja [62]

Please explain more...

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3 years ago

Read 2 more answers

PLS HELP WILL AWARD BRAINLIST!!!! PLS HELP DUE Tomorrow

Serhud [2]

Answer:

72º

Step-by-step explanation:

Angles at a point = 360º

Number of wedges = 5

Angle of each wedge

= 360 ÷ 5

= 72º

3 0

3 years ago