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sattari [20]
2 years ago
6

Find the area of a rectangle that length is 7n^2 +3n and width 2n^3

Mathematics
1 answer:
WITCHER [35]2 years ago
4 0

Answer:a

Step-by-step explanation: avnvgjv

A

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Solve the following equation for y.
labwork [276]

Answer:

17

Step-by-step explanation:

2y+2=36

Let's solve this equation for 2y first.  This means get 2y by itself.

So to get 2y by itself I need to undo that addition of 2 next to it.

The inverse operation of addition is subtraction.

I'm going to subtract 2 on both sides:

2y      =36-2

2y      =34

Now we want to get y by itself so we divide both sides by 2 since division and multiplication are inverse operations:

 y=        34/2

 y=        17

3 0
3 years ago
Read 2 more answers
Candice bought 6 dozen eggs and broke 9 eggs how many eggs did she have left
Nadya [2.5K]

Answer:

63

Step-by-step explanation:

12x6=72

72-9=63

the answer is 63

3 0
2 years ago
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Type the correct answer in the box. Use numerals instead of words.
Karo-lina-s [1.5K]

Answer:

6

Step-by-step explanation:

A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation y = mx + b.

If a line has the slope of -0.5, then m=-0.5 and the equation of the line is

y=-0.5x+b

This line passes throughthe point (10,1), then the coordinates of this point satisfy the equation of the line:

1=-0.5\cdot 10+b\\ \\1=-5+b\\ \\b=1+5\\ \\b=6

and the equation of the line is

y=-0.5x+6

Since b=6, the y-intercept of the line is 6.

7 0
3 years ago
Read 2 more answers
The radius of a circle is 6 inches. What is the circle's circumference?<br> Use 3.14 for ​.
Vikentia [17]

Answer:

37.68 inches

Step-by-step explanation:

The equation for the circumference of the circle is:

C=2\pi r

We can substitute 6 in for "r" and 3.14 for "π":

C=2(3.14)(6\ in)\\C=12\ in(3.14)\\C=37.68\ in^

4 0
2 years ago
A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th
mrs_skeptik [129]
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2).  Draw this to verify this statement.  Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height).  Subst. the values discussed above,   A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2).  Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section.   Doing the problem this way, we get (1/4) (3 sqrt(2) )^2.  Thus, 
A = (1/4) (9 * 2) = (9/2).  Same answer as before. 
4 0
3 years ago
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