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2 years ago

Between what two limits , expressed in degrees , are all acute angles found? All obtuse angles?

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

Answer:

Acute angles are less than 90 degrees, obtuse angles are more than 90 degrees, and right angles are exactly 90 degrees.Step-by-step explanation:

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A company makes bicycles in two sizes. The first bicycle size weighs 18.5 pounds. The second bicycle sizes weighs 1/14 as much a

QveST [7]

The second bicycle would weigh 1.32142857143 pounds or rounded to 1.32.
You would find this by multiply 18.5 by 1/14

7 0

2 years ago

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Which expression is equivalent to 9 p minus 3 p + 2?

Snezhnost [94]

Answer:

Didn't know how far I was needed to go, but I hope something there helps you.

Step-by-step explanation:

9p - 3p +2 = 0

6p +2 = 0

6p = -2

p = -2/6

p = -1/3

5 0

3 years ago

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During apple-picking season, 7 out of every 10 apples that are picked have a leaf attached to their stem. If Jackson picked 210

nekit [7.7K]

Answer:170

Step-by-step explanation:

Multiply 210 by 0.70 because that's equal to 70%. This will give you the answer.

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3 years ago

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Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago

If <5 is 63 degrees find the measure of <3.

Hatshy [7]

<5 = <1 = <4 = <8 = 63

Straight line = 180

180 - 63 = 117

<3 = 117

6 0

3 years ago