Which two parallelograms have the same area?
2 answers:
You might be interested in
Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± = ± i ( noting that
= i ), and
x² = - 5 ( take the square root of both sides )
x = ± = ±
= ±
×
= ± i
Solutions are x = ± i and x = ± i
Answer:
Step-by-step explanation:
<u>Given that:</u>
ΔUVW,
Side w = 44 cm, (It is the side opposite to )
Side u = 83 cm (It is the side opposite to )
and ∠V=141°
Please refer to the attached image with labeling of the triangle with the dimensions given.
Area of a triangle with two sides given and angle between the two sides can be formulated as:
Where a and b are the two sides and
is the angle between the sides a and b
Here we have a = w = 44cm
b = u = 44cm
and ∠C= ∠V=141
Putting the values to find the area:
So, the <em>area </em>of given triangle to the nearest square centimetre is:
