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2 years ago

How do you get domain and range

Mathematics

2 answers:

Lunna [17]2 years ago

7 0

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

Luba_88 [7]2 years ago

6 0

Step-by-step explanation:

the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

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Which of the following numbers can be expressed using negative exponents? Select one: a. .0005216 b. 5,216 c. -5,216 d. 52.16

Andreas93 [3]

Answer:

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Step-by-step explanation:

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2 years ago

betty closes the nozzle and fills it completely with a liquid. She then opens the nozzle. If the liquid drips at the rate of 14

natta225 [31]

Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

Shape: Cone

$r = 3$ -- radius

$h = 7$ --- height

$Rate = 14in^3/min$

Required

Time to pass out all liquid

First, calculate the volume of the cone.

This is calculated as:

$V = \frac{1}{3} \pi r^2h$

This gives:

$V = \frac{1}{3} * 3.14 * 3^2 * 7$

$V = \frac{1}{3} * 197.82$

$V = 65.94in^3$

To calculate the time, we make use of the following rate formula.

$Rate = \frac{Volume}{Time}$

Make Time the subject

$Time= \frac{Volume}{Rate }$

This gives:

$Time= \frac{65.94in^3}{14in^3/min}$

$Time= \frac{65.94in^3}{14in^3}min$

Cancel out the units

$Time= \frac{65.94}{14} min$

$Time= 4.71 min\\$

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2 years ago

(-2 + 1)² + 5(12 3) - 9.<br> The value of the expression is ?

Mumz [18]

Answer:

The total value of the given expression is 12.

Step-by-step explanation:

(-2 + 1)² + 5(12 ÷ 3) - 9

First, do the expressions within the parentheses.

(-1)² + 5(4) - 9

Next, simplify the exponents.

1 + 5(4) - 9

Next, multiply 5 by 4.

1 + 20 - 9

Add 1 and 20 together.

21 - 9

Subtract 9 from 21.

So, the final answer to this equation is 12.

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3 years ago

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Ronch [10]

Answer:

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Step-by-step explanation:

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2 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second