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3 years ago

A farmer plants a new type of corn and wants to quickly determine the yield, or total number of ears of corn, for the

Mathematics

1 answer:

miss Akunina [59]3 years ago

4 0

Answer:

The statement which is not true about the sample is;

The sample of 10 plants was a census of the corn plants

Step-by-step explanation:

The statement out of the given statements which is not true about the sample is "The sample of 10 plants was a census of the corn plants"

The 10 unique number corn which the farmer randomly selects of which he then count the number of ears in the corn and multiply by 100 so as to quickly arrive at an estimate of the total number of ears of corn for the crop, without individually counting the ears on each plant from the 100 plants

A census is a counting and individual enumeration procedure to collect and record characteristic information and details of the all the members that make up a given population

Therefore, the farmer is finding an estimate of the number of ears of in the plants rather than taking a census of the ears of corn on each plants in the population of 100 plants

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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

3 years ago

Luiza is jumping on a trampoline.

lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0

3 years ago

Find the Circumference of the circle. Use 3.14 for π. Round your answer to the nearest tenth.

kotykmax [81]

Answer:

28.3 cm

Step-by-step explanation:

The formula to find the circumference is 2•π•radius. The diameter is 9 cm, so the radius is 9/2 = 4.5 cm. So, the circumference is:

2•4.5•3.14 = 28.26 ≈ 28.3 cm

8 0

3 years ago

A student solves the equation for v. Start with the original equation. Use the square root property. Use the division property o

LekaFEV [45]

Answer:

the answer is d

<em>The square root property should have been applied to both complete sides of the equation instead of to select variables. </em>

<em />

Step-by-step explanation: i just took the test on edge

5 0

3 years ago

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zaharov [31]

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