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Leno4ka [110]
3 years ago
10

Richard goes to the electronic store. he buys two memory cards that cost $8.99 each and three packages of batteries that are on

sale for $7.49 each. he also buys a case for his cell phone for $2.99 and a wireless headset for $29.99. what is the total cost of Richard's items, before sales tax?
Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

$8.99x3+7.47x3+2.99+29.99=73.37 so the total cost for all of the items $73.37. Hope this helps :)

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miv72 [106K]

Answer:

(1)7 (2)9 (3)6

Step-by-step explanation:

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(1)The average rate of change between x=2 and x=5

\dfrac{dy}{dx} =\dfrac{f(5)-f(2)}{5-2} =\dfrac{32-11}{3} =\dfrac{21}{3} =7

(2)The average rate of change between x=3 and x=6

\dfrac{dy}{dx} =\dfrac{f(6)-f(3)}{6-3} =\dfrac{43-16}{3} =\dfrac{27}{3} =9

(3)The average rate of change between x=2 and x=4

\dfrac{dy}{dx} =\dfrac{f(4)-f(2)}{4-2} =\dfrac{23-11}{2} =\dfrac{12}{2} =6

7 0
3 years ago
Derive the equation of the parabola with a focus at (-5,5) and a directix of y = -1
Paladinen [302]

Answer:

D

Step-by-step explanation:

From any point (x, y) on the parabola the focus and directrix are equidistant

Using the distance formula

\sqrt{(x+5)^2+(y-5)^2} = | y + 1 |

Squaring both sides

(x + 5)² + (y - 5)² = (y + 1)^2 , that is

(y + 1)² = (x + 5)² + (y - 5)² ← subtract (y - 5)² from both sides

(y + 1)² - (y - 5)² = (x + 5)² ← expand left side and simplify

y² + 2y + 1 - y² + 10y - 25 = (x + 5)²

12y - 24 = (x + 5)² ← factor left side

12(y - 2) = (x + 5)² ← divide both sides by 12

y - 2 = \frac{1}{12} (x + 5)² ← add 2 to both sides

y = \frac{1}{12} (x + 5)² + 2

or

f(x) = \frac{1}{12} (x + 5)² + 2 → D

7 0
3 years ago
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baherus [9]

Answer:

Option (2)

Step-by-step explanation:

In the two triangles ΔWVZ and ΔYXZ,

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Therefore, ΔWVZ ~ ΔYXZ [By AA postulate of the similarity]

Option (2) will be the answer.

4 0
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A laboratory scale is known to have a standard deviation of Ï = 0.001 gram in repeated weighings. Scale readings in repeated wei
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Answer:

the confidence interval for the true weight of the specimen is;

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Thus, the confidence interval for the true weight will be expressed as;

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Answer:

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2 years ago
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