10) S is the midpoint of RT.
Sx= Rx+Tx/2=2
Tx=13
Sy=Ry+Ty/2= -1
Ty= -1
T=(13,-1)
11) Sx=Rx+Tx/2=-4
Rx= -1
Sy=Ry+Ty/2= -6
Ry= -9
R=(-1,-9)
12)B is midpoint of AC.
Bx= Ax+Cx/2=-5
By= Ay+Cx/2= 1
B=(-5,1)
E is midpoint of BD.
Ex= Bx+Dx/2=-4
Dx=-3
Ey=By+Dy/2=-3
Dy=-7
D=(-3,-7)
Answer: I think the answer is 19
Step-by-step explanation:
pls mark brainliest
Answer:
j(x) is shifted right by units
Step-by-step explanation:
Given
Required
Determine the transformation from j(x) to k(x)
The transformation shows a horizontal shift from j(x) to k(x).
First, we need to determine the unit shifter from j(x) to k(x) as follows;
Express as
So:
becomes
Reorder
Comparing this to k(x), we have:
In other words:
<em>This implies that j(x) is shifted right by </em><em> units</em>
Answer:
1/9 :)
Step-by-step explanation:
use the power rule, square both numerator and denominator, 1^2 = 1 3^2 = 9
hope this helps!!!!