Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
Yes, but this must be done before the withdraw deadline
Explanation:
TopHat is an online learning platform. Students register for courses and if they decide not to continue with a course for reasons best known to them, they are allowed a time period usually one to two weeks to drop the courses. They are then reimbursed the fee for that particular course.
But if that time period elapses and they drop the course, that is considered a withdrawal that is not accepted and which no provisions for reimbursements are made.
Make sure that each box has an arrow going to it or leading from it, if it needs one. Select “Insert,” then “Shapes,” and choose the Text Box option: Page 2 [Algorithm how-to procedure] 2 Drag the cursor across the document to customize the size of the text box. Click inside the box to begin typing.
brainliest pls
Answer:
The program to this question as follows:
Program:
targetValue = 0.3333 #defining variable targetValue and assign value
sensorReading = 0.0 #defining variable sensorReading and assign value
sensorReading = 1.0/3.0 #calculate value in sensorReading variable
Val=sensorReading - targetValue
#calculate the difference and store in Val variable
if (Val < 0.0001): #use of if block to check condition
print ("Equal") #print value
else: #else block
print ("Not equal") #print value
Output:
Equal
Explanation:
In the above Python program code, there are two variables "targetValue and sensorReading" is defined, in which targetValue store a value, that is "0.3333", and sensorReading holds a value, that is "0.0".
- In the next step, the "Val" variable is defined, that calculate the difference between both variable, that conditional statement is used.
- In if block, if the value is less then "0.0001", it will print value "Equal", otherwise, it will go to the else block, that will print "Not equal".
The data that is transmitted in plain text is option D: cryptographic failure.
<h3>An established plain text only assault is what?</h3>
The known-plaintext attack (KPA) is a cryptanalysis assault type where the attacker has access to both the encrypted and plaintext versions of the data (also known as a crib) (ciphertext). These can be used to reveal additional hidden information, including code books and secret keys.
Therefore, Plaintext in the context of cryptography typically refers to unencrypted data that is being prepared for input into cryptographic techniques, typically encryption algorithms. Typically, unencrypted data transmission or storage falls under this category.
Learn more about data transmission from
brainly.com/question/10564419
#SPJ1
