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Blababa [14]
2 years ago
6

A machine cuts a strip of carpet into two pieces. The length of the smaller piece is 5 meters greater than 1/4 the length of the

larger piece. If the length of the smaller piece is 12 meters, the length of the bigger piece is (?)
meters and the total length of the carpet is (?)
meters.
Mathematics
2 answers:
Zanzabum2 years ago
5 0

Answer:

17 meters

Step-by-step explanation:

pav-90 [236]2 years ago
3 0
17 meters hipiggipkk
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EASY MATH (no links or get reported)
katovenus [111]

Answer:

Find the Roots (Zeros) f(x)=x^3-6x^2+13x-20. f(x)=x3−6x2+13x−20 f ( x ) = x 3 - 6 x 2 + 13 x - 20. Set x3−6x2+13x−20 x 3 - 6 x 2 + 13 x - 20 equal to 0 0 .

Step-by-step explanation:

hope this helps

4 0
3 years ago
Decreace £2500 by 1%
kondaur [170]
Ok, if you decrease <span>£2500 by 1% you get 99% remaining
</span>So
99% of £2500 = 0.99 x £2500 = <span>£2475</span>
6 0
3 years ago
Helpppppppppp Meeeeeeeeeee Plssssssssss Problemmm 3
Fudgin [204]
(-3,2) (0,0) i think. it’s been a whole
4 0
3 years ago
Triangle ABC is an isosceles triangle in which side
Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using this formula, we get

AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5

BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}

AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5

Now,

Perimeter of triangle ABC = AB + BC + AC

                        =5+\sqrt{10}+5

                        =10+\sqrt{10}

So, perimeter of triangle ABC is 10+\sqrt{10} units.

Therefore, the correct option is B.

4 0
3 years ago
Read 2 more answers
Arc AB is One-sixth of the circumference of a circle. What is the radian measure of the central angle? StartFraction pi over 6 E
oksian1 [2.3K]

Answer:

StartFraction pi Over 3 EndFraction

Step-by-step explanation:

we know that

The circumference of a circle subtends a central angle of 360 degrees or 2π radians

so

by proportion

Find out the central angle for an arc equal to One-sixth of the circumference of a circle

Let

x -----> the measure of the central angle in radians for an arc equal to One-sixth of the circumference

\frac{C}{2\pi}=\frac{(C/6)}{x}\\\\x=2\pi(C/6)/C\\\\x=\frac{2\pi}{6}

Simplify

x=\frac{\pi}{3}

therefore

StartFraction pi Over 3 EndFraction

5 0
3 years ago
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