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anygoal [31]
2 years ago
15

A technical machinist is asked to build a cubical steel tank that will hold of water. Calculate in meters the smallest possible

inside length of the tank. Round your answer to the nearest .
Mathematics
1 answer:
Charra [1.4K]2 years ago
5 0

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

Volume = 565L

Required

The smallest length of the tank

Since the tank is cubical, then the volume is:

Volume = Length^3

This gives:

565L= Length^3

Express as m^3

\frac{565m^3}{1000} = Length^3

0.565m^3 = Length^3

Take cube roots of both sides

0.8267m = Length

Rewrite as:

Length = 0.8267m

Approximate

Length = 0.83m

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Gwar [14]

Answer: A) intercepts: zero profit; maximum: maximum profit. increasing: x < 4; decreasing x > 4

 B) average slope: ≈50, about $50 increased profit for each $1 increase in price.

Step-by-step explanation:

A) The vertical axis of the graph represents profit, so the x-intercepts represent prices that produce zero profit. The maximum value of the graph is the maximum profit that can be obtained for any price.

The function is increasing for all prices below the one producing maximum profit (x < 4). The function is decreasing for all prices above the one producing maximum profit (x > 4). Obviously profit is increasing with price for x < 4, and is decreasing with price for x > 4.

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B) We read the value of f(1) from the graph to be about 120, so the average rate of change is about ...

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* If we take the peak profit to be $270, we can write f(x) as ...

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Step-by-step explanation:

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2 years ago
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A plane at 3,800 feet is descending at a rate of 120 feet per minute, and a plane at 520 feet is climbing at a rate of 40 feet p
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Answer:

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