Question

A technical machinist is asked to build a cubical steel tank that will hold of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .

Answer 1

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

$Volume = 565L$

Required

The smallest length of the tank

Since the tank is cubical, then the volume is:

$Volume = Length^3$

This gives:

$565L= Length^3$

Express as $m^3$

$\frac{565m^3}{1000} = Length^3$

$0.565m^3 = Length^3$

Take cube roots of both sides

$0.8267m = Length$

Rewrite as:

$Length = 0.8267m$

Approximate

$Length = 0.83m$