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Is 9.4 is the same thing as 9/4

Yakvenalex [24]

No, if you were to convert 9/4 into a decimal it would be 2.25.

6 0

4 years ago

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Pls solve quickly !!

Eva8 [605]

Answer:

Options A

Step-by-step explanation:

Properties of the graph given for the function 'g',

y-intercept of the function 'g' → y = -4

Minimum value of g(x) → y = -4 (Value of the function at the lowest point)

Roots of g(x) → x = -2, 2

At x = 4,

g(4) = 11

Another function is,

f(x) = -x² - 4x - 4

= -(x² + 4x + 4)

= -(x + 2)²

Properties of the function f(x) = -(x + 2)²,

y-intercept (at x = 0) of the function 'f',

y = -(x + 2)²

y = -4

Since, leading coefficient of the function is (-1) therefore, graph will open downwards and the maximum point will be its vertex.

Maximum value of the function 'f' = Value of the function at the vertex

Coordinates of vertex → (-2, 0)

Therefore, maximum value of 'f' = 0

Roots (at y = 0) of the function 'f' → x = -2

At x = 4,

f(4) = -(4 + 2)²

= -36

Therefore, Options A will be the correct option.

5 0

3 years ago

A phone manufacturer wants to compete in the touch screen phone market. Management understands that the leading product has a le

CaHeK987 [17]

Answer:

Step-by-step explanation:

Hello!

To compete in the touch screen phone market a manufacturer aims to release a new touch screen with a battery life said to last more than two hours longer than the leading product which is the desired feature in phones.

To test this claim two samples were taken:

Sample 1

X: battery lifespan of a unit of the new product (min)

n= 93 units of the new product

mean battery life X[bar]= 8:53hs= 533min

S= 84 min

Sample 2

X: battery lifespan of a unit of the leading product (min)

n= 102 units of the leading product

mean battery life X[bar]= 5:40 hs = 340min

S= 93 min

The population variances of both variances are unknown and distinct.

To test if the average battery life of the new product is greater than the average battery life of the leading product by 2 hs (or 120 min) the parameters of interest will be the two population means and we will test their difference, the hypotheses are:

H₀: μ₁ - μ₂ ≤ 120

H₁: μ₁ - μ₂ > 120

Considering that there is not enough information about the distribution of both variables, but both samples are big enough, we can apply the central limit theorem and approximate the distribution of both sample means to normal, this way we can use the standard normal:

$Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} } }$

Z≈N(0;1)

$Z= \frac{(533-340)-120}{\sqrt{\frac{84^2}{56} +\frac{93^2}{102} } }= 5.028$

I hope this helps!

3 0

4 years ago

The graph represents f(x), and g(x) = 7x – 42.

Aliun [14]

$g(x)=7x-42\\\\\y-intercept\ of\ g(x):\\\\f(0)=7\cdot0-42=-42\to(0;\ -42)\\\\x-intercept\ of\ g(x):\\\\0=7x-42\ \ \ \ |+42\\7x=42\ \ \ |:7\\x=6\to(6;\ 0)$

$f(x)=ax+b\\\\y-intercept\ of\ f(x):\ (0;\ -3)\\\\x-intercept\ of\ f(x):\ (6;\ 0)$

Answer:

A) the y-intercept of g(x) is less than the y-intercept of f(x).

4 0

4 years ago

What is 7/14 fractions im in class and i dont know.? Can anyone help me????.

agasfer [191]

Answer:

$\frac{7}{14} = \frac{1}{2}$

Step-by-step explanation:

4 0

3 years ago

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Don’t use a calculator Show your work pls DONT USE ANY LINKS