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Fofino [41]
4 years ago
6

Which of the following transformations will make coincide with ?

Mathematics
1 answer:
blagie [28]4 years ago
6 0

Answer:

D. Translation 1 unit up and 5 units to the right, followed by a reflection across the x-axis

Step-by-step explanation:

→ Point B moves up to [-2, -4]

Translation up:

→ Point A moves up to [-5, -1]

→ Point B moves up to [3, -4]

Translation to the right:

→ Point A moves up to [0, -1]

→ [3, -4] >> <em>B'</em>[3, 4]

Reflections:

→ [0, -1] >> <em>A'</em>[0, 1]

This is a genuine statement!

I am joyous to assist you anytime.

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Please help! please show the work and not give me and answer thank you ❤️
Citrus2011 [14]

Ans. 1 Angle E and angle F are corresponding angles.

Solution 2.

So,

angle E = angle F

=> x + 20 = 5x - 20

=> x + 20 + 20 = 5x

=> x + 40 = 5x

=> 40 = 5x - x

=> 40 = 4x

=> 40/4 = x

=> 10 = x

Solution 3.

E = x + 20

=> E = 10 + 20

=> E = 30

F = 5x - 20

=> F = 5(10) - 20

=> F = 50 - 20

=> F = 30

<em>Again</em><em> </em><em>justified</em><em> </em><em>that </em><em>they </em><em>are </em><em>equal</em><em> (</em><em> </em><em>besides</em><em> </em><em>answer </em><em>1</em><em>)</em><em>.</em>

8 0
3 years ago
What is the greatest common factor of 18 and 3?
-Dominant- [34]
3 is your greatest 

3/3 = 1

18/3 = 6


hope this helps
8 0
3 years ago
NEED ASAPPPP
Ber [7]

Answer:

(-3,4)

Step-by-step explanation:

to solve for x, make y=0

to solve for y, make x=0

3 0
3 years ago
Read 2 more answers
The height of an object tossed upward with an initial velocity of 120 feet per second is given by the formula h = −16t2 + 120t,
AleksAgata [21]

Answer:

7.5 seconds

Step-by-step explanation:

h =  - 16 {t}^{2}  + 120t \\  \because \:  we \: have \: to \: find \:  the  \:  time  \: required  \:  \\ for \:  the \:  object \:  to \:  return to \:  its  \:  \\ point \:  of  departure. \\  \therefore \: plug \: h = 0 \: in \: the \: given \: euation. \\  \therefore \: 0 =   - 16 {t}^{2}  + 120t \\ \therefore \:16 {t}^{2}  - 120t = 0 \\ \therefore \:8t(2t - 15) = 0 \\ \therefore \:8t = 0 \:  \: or \:  \: (2t - 15) = 0 \\ \therefore \:t =  \frac{0}{8}  \: or \: t =  \frac{15}{2}  \\ \therefore \:t = 0 \: or \: t = 7.5 \\  \because \: t = 0 \: is \: not \: possible \\ \huge \purple{ \boxed{  \therefore \: t = 7.5 \: seconds}}

Thus, the time required for the object to return to its point of departure is 7.5 seconds.

4 0
3 years ago
Which expression is equivalent to the given expression?
Rainbow [258]
C. Square root of 48
4 0
3 years ago
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