Answer:
x=0 y=-11 (0,-11)
Step-by-step explanation:
1. take what y equals (3x-11) and plug it in for y in the second equation
Should look like this: O= 6x-2(3x-11)-22
2. Then distribute O=6x-6x+22-22
3. Then combine like terms O= 0 the 22's cancel out as well as the x's
x= 0
4. plug 0 in for x in the first equation y=3(0)-11
5. y= -11
6. x=0 y=-11 (0,-11)
Answer:
(1,-44), (2,-48),(3,-52).......
Step-by-step explanation:
4(1)+y=-40
4+y=-40
y=-40-4
y=-44
(1,-44)
.
.
.
The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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Answer:
true, refer to picture for more understanding :)
