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tankabanditka [31]
3 years ago
13

Can someone tell me the area of this please

Mathematics
2 answers:
stepladder [879]3 years ago
7 0
Which one?Just multiply the sides, than the answer that you get use it and divide it by 2.
Andru [333]3 years ago
5 0

Answer: just multiply all sides with a calculator, that easy

Step-by-step explanation: or do you need help with solving it?

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The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 14
Salsk061 [2.6K]

<u>Question Completion</u>

PIE CHART NUMBERS:

  • Excellent 9%
  • Good 41%
  • Fair 36%
  • Poor 13%
  • Other 1%

Answer:

0.000063

Step-by-step explanation:

Number of Respondents, n=1400

Probability that they would rate their financial shape as​ excellent = 0.09

Number of Those who would rate their financial shape as excellent

=0.09 X 1400

=126

Therefore:

The probability that 4 people chosen at random would rate their financial shape as​ excellent

=\dfrac{^{126}C_4 \times ^{1400-126}C_0}{^{1400}C_4} \\=\dfrac{^{126}C_4 \times ^{1274}C_0}{^{1400}C_4}\\=0.000063 $(correct to 6 decimal places)

6 0
3 years ago
5y+4 times 2 what is the coefficient in this expression?
rodikova [14]

Answer: 5

Step-by-step explanation: The coefficient is the number that comes right before the variable. Another way to say this is it's what the variable is multiplied by.

3 0
3 years ago
a basketball team played five games . in those games , the team won by 7 points , lost by 3 , won by 4, lost by 2 , and won by 9
Paul [167]

Answer: 3

Step-by-step explanation:

7-3+4-2+9=15

15/5=3

6 0
2 years ago
How many milliliters are in 5 liters?
blsea [12.9K]

Answer:

There are 5000 mililitres in 5 litres

Therefore option A.

Hope u got the answer............

5 0
2 years ago
If ​f(x)=x^2- 4 and ​g(x)=x^2 plus 2 x​,
gregori [183]

Answer:

\huge\boxed{(f-g)\left(-\dfrac{1}{3}\right)=-3\dfrac{1}{3}}

Step-by-step explanation:

\text{We have}:\\\\f(x)=x^2-4\ \text{and}\ g(x)=x^2+2x\\\\(f-g)(x)=f(x)-g(x)\\\\\text{therefore}\\\\(f-g)(x)=(x^2-4)-(x^2+2x)=x^2-4-x^2-2x\\\\=(x^2-x^2)-2x-4=-2x-4\\\\(f-g)\left(-\dfrac{1}{3}\right)\to\text{put}\ x=-\dfrac{1}{3}\ \text{to the equation of the function}\ (f-g)(x):\\\\(f-g)\left(-\dfrac{1}{3}\right)=-2\left(-\dfrac{1}{3}\right)-4=\dfrac{2}{3}-4=-3\dfrac{1}{3}

6 0
3 years ago
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