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SOVA2 [1]
3 years ago
15

Evaluate the expression below.

Mathematics
2 answers:
liubo4ka [24]3 years ago
7 0

Answer:

1

Step-by-step explanation:

Pemdas

parenthesis

exponent

multiply

divide

add

subtract

|8-7|*4+3(-1)

8-7=1

1*4+3(-1)

3(-1)=3

1*4-3

1*4=4

4-3=1

1 is the correct answer.

o-na [289]3 years ago
6 0

Answer:

<h2>A. 1</h2>

Step-by-step explanation:

Use:

|a| = a for a ≥ 0 or |a| = -a for a < 0

PEMDAS:

P Parentheses first

E Exponents

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

========================================

|8 - 7| · 4 + 3(-1)

= |1| · 4 - 3

= 1 · 4 - 3

= 4 - 3

= 1

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A.

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If the 5th term of a geometric progression is 162 and the 8th term is 4374, find the (i) 1st three terms of the sequence; (ii) s
Alona [7]

Answer:

see explanation

Step-by-step explanation:

The nth term of a geometric progression is

a_{n} = a₁r^{n-1}

where a₁  is the first term and r the common ratio

Given a₅ = 162 and a₈ = 4374 , then

a₁r^{4} = 162 → (1)

a₁r^{7} = 4374 → (2)

Divide (2) by (1)

\frac{a_{1}r^{7}  }{a_{1}r^{4}  } = \frac{4374}{162}

r³ = 27

r = \sqrt[3]{27} = 3

Substitute r = 3 into (1) and solve for a₁

a₁(3)^{4} = 162

81a₁ = 162

a₁ = \frac{162}{81} = 2

Then

a₂ = a₁ × 3 = 2 × 3 = 6

a₃ = a₂ × 3 = 6 × 3 = 18

The first 3 terms are 2, 6, 18

(ii)

The sum to n terms of a geometric progression is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1} , then

S_{10} = \frac{2(3^{10}-1) }{3-1}

     = \frac{2(59049-1)}{2}

     = 59049 - 1

     = 59048

   

6 0
3 years ago
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