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3 years ago

14

What are the odd of rolling two number cubes and getting the sum of 7

1 answer:

emmasim [6.3K]3 years ago

8 0

Number of possible outcomes of one cube = 6
<span>Number of possible outcomes of the other cube = 6 </span>
<span>Number of possible outcomes of two cubes = 6 x 6 = 36 </span>

<span>Number of ways to roll a sum of 7 with two cubes = 6 </span>

<span>1 - 6 </span>
<span>2 - 5 </span>
<span>3 - 4 </span>
<span>4 - 3 </span>
<span>5 - 2 </span>
<span>6 - 1

</span>

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Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...

svlad2 [7]

Answer:

The required recursive formula is:

$a_n=(-3)\times a_{n-1}$

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let $a_n$ represents the nth term of the sequence.

This means that:

$a_1=6, a_2=-18, a_3=54, a_4=-162,......$

As the common ratio is -3.

so,

$a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}$

Hence, the required recursive formula for the geometric sequence is:

$a_n=(-3)\times a_{n-1}$

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3 years ago

Two sides of a triangle measure 10 inches and 13 inches. The included angle between these sides is 55°. What is the approximate

PolarNik [594]

The answer should B 11.2 inches

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2 years ago

Hi, can someone please help, and possibly explain the answer please.

mr_godi [17]

Answer:

$x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

Step-by-step explanation:

Quadratic formula: $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ when the equation is $0=ax^2+bx+c$

The given equation is $1=-2x+3x^2+1$ . Let's first arrange this so its format looks like $y=ax^2+bx+c$ :

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$1=3x^2-2x+1$

Subtract 1 from both sides of the equation

$1-1=3x^2-2x+1-1\\0=3x^2-2x+0$

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

I hope this helps!

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Maksim231197 [3]

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