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2 years ago

Find the slope of the line y= -2/3x

Mathematics

1 answer:

kodGreya [7K]2 years ago

3 0

The slope is -2/3.
_______________________________

Explanation:

y=mx+b

m= slope

-2/3=m

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Quadrilateral ABCD is inscribed in this circle.

Alecsey [184]

The sum of all interior angles in a polygon is

180(n-2), where n = sides, well, this is a QUADrilateral, so it has 4 sides, so the total is 360°.

now, let's find what angle C is first,

$\bf \stackrel{A}{(2x-40)}+\stackrel{B}{(116)}+C+\stackrel{D}{(x)}=360\implies C+3x+76=360
\\\\\\
C+3x=284\implies C=284-3x$

now, recall the "inscribed quadrilateral conjecture", where opposite angles are "supplementary angles", thus

$\bf \stackrel{\measuredangle A}{(2x-40)}+\stackrel{\measuredangle C}{(284-3x)}=180\implies -x+244=180
\\\\\\
64=x\\\\
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\measuredangle A=2(64)-40$

8 0

3 years ago

Read 2 more answers

PLEASSSsSEEeeE HeLPpPp

prisoha [69]

Answer:

D = 59t

P = 42t

5 hours after noon, darmian is 17 miles closer to the stadium than paisley

Step-by-step explanation:

At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.

Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.

At t hours after noon, their distance covered will be;

Damian; D = 59t

Paisley; P = 42t

This is because distance = speed × time

Now, 5 hours after noon, their respective distance covered will be;

D(5) = 59 × 5 = 295 miles

P(5) = 42 × 5 = 210 miles

This means that;

distance of Damian from the stadium is; 383 - 295 = 88 miles

Distance of paisley from the stadium is;

315 - 210 = 105 miles

Difference in their distances to the stadium = 105 - 88 = 17 miles

Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley

4 0

2 years ago

Problem 1. (1 point) A steel ball weighing 128 pounds is suspended from a spring. This stretches the spring 128101 feet. The bal

stepladder [879]

Answer:

seeed

Step-by-step] explanation:

ddd~!`

7 0

2 years ago

Please! Solve f(x)-g(x) if f(x)=1/2x^4 - x^2 and g(x)= 3/4x^4 +3x^3 - x^2

igomit [66]

Answer:

$f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}$

Step-by-step explanation:

This is a subtraction between polynomials, since both functions are polynomials, hence, to solve the problem with need to perform the subtraction, by coefficients.

$f(x)= \frac{1}{2}x^{4}+0x^{3}-x^{2}\\\\g(x)=\frac{3}{4}x^{4}+3x^{3}-x^{2}$

By performing the subtraction, we have:

$f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}$

6 0

2 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

2 years ago