Answer:

Step-by-step explanation:
The distance between the focus and the directrix is the vertical distance from the point to the line:
1 -(-3) = 4
The vertex is half that distance between the point and the line, so is at x=2 and ...
y = (-3 +1)/2 = -1
The vertical scale factor of the quadratic is 1/(4p) where p is the distance from vertex to focus. Here, that distance is 2, so the equation in vertex form is ...
y = (1/(4·2))(x -2)² -1
y = (1/8)(x -2)² -1
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<em>Check</em>
Any point on the parabola is equidistant from the focus and directrix. This is easily checked at the vertex, which is halfway between focus and directrix, and at the points having the same y-value as the focus. Those two points are (-2, 1) and (6, 1), both of which are 4 units from the focus and 4 units from the directrix.
(Problems 1b and 2b are cut off in the photo)
1a Problem:
(-3,1)
(-3,5)
(-7,1)
2a Problem:
(6,2)
(3,5)
(10,7)
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I thank it is B you have to add all the tickets and times that by the the amount of money
<span>Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. f(x) = 3(4)(2x-4). h(x) = (x + 2)3 + 1.
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D) x= 4</span>