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2 years ago

PLEASE ANSWER ASAP! REALLY IMPORTANT! MUST BE CORRECT! POINTS GIVEN!

Mathematics

2 answers:

VMariaS [17]2 years ago

8 0

- 5/12 + ( - 1/4) =

Adding two negatives results in a negative

-1/4 = -3/12

-3/12 + -5/12 = -8/12

-8/12 + 3/12 < Subtract and take the sign of the BIGGER number.

8 - 3 = 5

- 5/12

Answer: - 5/12

OLga [1]2 years ago

7 0

-5/12 - 1/4 + 3/12

To add fractions, they must all have the same denominator.
Change the -1/4 to twelfths:

   -1/4 = -3/12 .

So now the problem is

   - 5/12 - 3/12 + 3/12

Notice that the -3/12 and the +3/12 knock each other out,
and all you're left with is
   - 5/12 .

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I need so much help

laiz [17]

Question (1):

Price last week = $6.00
Price this week = $7.20

Increased = $7.20 - $6.00 = $1.20

Answer : Percentage increased = $1.20/$6.00 x 100 = 20%

Question (2):

Original Price = $90

Marked down = 35% of $90 = 0.35 x 90 = $31.50

Price after marked down = $90 - $31.50 = $58.50

Answer: Lilly will pay $58.50 for the football cleats.

6 0

3 years ago

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QUESTION ATTACHED PLZ HELP NEEDED

saw5 [17]

Y = a (x + 3)² - 1

Let's take the point (-1;3)

3 = a ( -1 + 3)² - 1
3 = 4a - 1
4a = 4

Therefore a = 4/4 = 1

(x+3)² - 1
= x² + 6x + 9 - 1
= x² + 6x + 8

The answer would be y = x² + 6x + 8.

Hope this helps !

Photon

4 0

3 years ago

I’m need this worked out step by step by tonight

Pie

9514 1404 393

Answer:

-3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

-7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

-14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

-9 ≤ 3x ≤ 19

Divide all parts by 3.

-3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

|(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

|f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

8 0

2 years ago

Which equation represents a circle that contains the point (-5,-3) and has a center at (-2,1)

MatroZZZ [7]

Answer:

The equation of circle is:

Solution:

The general form of equation is given as:

Where, "r" is radius of circle and (a, b) is center of circle

Given that center at (-2, 1)

a = -2 and b = 1

Substitute (a , b) = (-2, 1) and (x, y) = (-5, -3) in general equation

Substitute r = 5 and (a, b) = (-2, 1) in general equation

Thus the equation of circle is found

4 0

3 years ago

Help me please with this

Nutka1998 [239]

Answer:

Step-by-step explanation:

Solving the inequality

$\frac{x+3}{6}$ > $\frac{x}{4}$ + 1

Multiply through by 12 ( the LCM of 6 and 4 ) to clear the fractions

2(x + 3) > 3x + 12

2x + 6 > 3x + 12 ( subtract 2x from both sides )

6 > x + 12 ( subtract 12 from both sides )

- 6 > x , that is

x < - 6

The only value less than - 6 is - 10

Thus x = - 10 is a solution to the inequality

8 0

2 years ago

Read 2 more answers