The required probability is
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that,
Probability for first draw to be non-defective
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective
(printers after first slot = 10; total defective printers = 2)
Then, total probability
The growth factor of the exponential function represented by the table is 5.
The correct option is c.
<h3>What is the growth factor of the exponential function?</h3>
The growth factor of the exponential function is the ratio of the two consecutive terms (y-values).
The growth factor of the exponential function is given by;
As per given, we have a table;
x y
-2 0.004
-1 0.02
0 0.1
1 0.5
The value is -2 and is -1.
Therefore,
the growth factor of the exponential function represented by the table would be :
Hence, the growth factor of the exponential function represented by the table is 5.
To know more about the Growth factor click the link given below.
brainly.com/question/985668
Distribute to eliminate the parenthesis
x^2 + 2x + 6x + 12 = 60
Combine like terms
x^2 + 8x + 12 = 60
Subtract 60 from both sides
x^2 + 8x - 48 = 0
Factor the equation
(x+12)(x-4)=0
x+12=0
x+4=0
x= -12 and -4
Answer:
g(x) = x^2 -6x +9
Step-by-step explanation:
A function f(x) translated right h units and up k units will become ...
g(x) = f(x -h) +k
You want the function f(x) = x^2 to be translated right h=3 units, so it will become ...
g(x) = f(x -3) = (x -3)^2
g(x) = x^2 -6x +9
Answer:
a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)
Step-by-step explanation:
Let's solve by separating variables:
a) x’=t–sin(t), x(0)=1
Apply integral both sides:
where k is a constant due to integration. With x(0)=1, substitute:
Finally:
b) x’+2x=4; x(0)=5
Completing the integral:
Solving the operator:
Using algebra, it becomes explicit:
With x(0)=5, substitute:
Finally:
c) x’’+4x=0; x(0)=0; x’(0)=1
Let be the solution for the equation, then:
Substituting these equations in <em>c)</em>
This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>
Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:
Finally: