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AfilCa [17]
3 years ago
8

Evaluate the expression 3x + 21 for x=3

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

30

Step-by-step explanation:

Problem = 3x + 21 for x=3

3(3) +21 --- subsitute the three for the x

9 + 21 ---- multiply the 3s together

30 ----- add

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Is p(x)= |x| an inverse function
docker41 [41]

Answer:

Step-by-step explanation:

p(x) = |x|

in : R  let : y = |x|

calculate : x

y² = |x| ²

y² = x²

y² - x²= ( y - x)( y +x) by identity

y = x or y = - x

the inverse : y = x or y = - x

conclusion : the inverse is : g(x) = |x|

4 0
3 years ago
Read 2 more answers
HELP HELP HELP I WILL GIVE BRAINLIEST <br> NO B.S. ANSWERS PLEASE
Whitepunk [10]
I believe it’s x=2.5 or x=2 1/2 or x=5/2
They are all the same answers in different forms . Hope it’s right
8 0
3 years ago
Find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1
kicyunya [14]

Given:

f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1

To find:

The correct function.

Explanation:

Let us consider the function given in option D.

f(x)=\frac{x^2}{2}-4x+5

Differentiating with respect to x we get,

\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}

Substituting x = 2 in the function f(x), we get

\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}

Therefore, the given conditions are satisfied.

So, the function is,

f(x)=\frac{x^{2}}{2}-4x+5

Final answer: Option D

6 0
1 year ago
Would I have to add all of them or multiply I can’t remember how to do it nor if I actually learned this.
nirvana33 [79]

Answer:

Multiply Length times Width times Height.

Step-by-step explanation:

sq root 24 x sq root 18 x sq root 8 = 58.78

5 0
3 years ago
Find the coordinates of midpoint F.
Mice21 [21]

Answer:

The coordinates are (0,b)

Step-by-step explanation:

Here, we want to find the coordinates of the midpoint F

as we can see, F is between A and B

we proceed to use the midpoint formula

The midpoint formula is;

(x,y) = (x1 + x2)/2, (y1 + y2)/2

(x1,y1) = (-3a, b)

(x2,y2) = (3a, b)

The substitution of these values will thus yield;

(-3a + 3a)/2, (b + b)/2

= (0/2), (2b/2)

= (0, b)

4 0
2 years ago
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