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3 years ago

I need help I’m stuck

Mathematics

1 answer:

cluponka [151]3 years ago

5 0

Answer:

Step-by-step explanation:

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Find the limit if it exists

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Answer:

20.

Step-by-step explanation:

When x = 2

f(x= 3(2)^3 + 2^2 - 8

= 24 + 4 - 8

= 20.

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3 years ago

Determine the domain and range of the graph below.

Leni [432]

Answer:

Last one

Step-by-step explanation:

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3 years ago

Plzz help me im am stuck

Pachacha [2.7K]

I hope this helps you!

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3 years ago

What is the volume of the sphere below?

Sindrei [870]

Answer: Option C.

Step-by-step explanation:

The volume of a sphere can be calculated with this formula:

$V=\frac{4}{3}\pi r^3$

Where "r" is the radius.

You can observe in the figure that the value of the radius of this sphere is:

$r=4\ units$

Then you can substitute this radius into the formula $V=\frac{4}{3}\pi r^3$ .

Therefore, the volume of the sphere shown in the figure is:

$V=\frac{4}{3}\pi (4units)^3$

$V=\frac{256}{3}\pi \ units^3$

3 0

3 years ago

Read 2 more answers

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Katyanochek1 [597]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

4 0

3 years ago