Answer:
A
Step-by-step explanation:
Replace the point (0,0) in each inequality
A. y - 4 < 3x - 1
B. y - 1 < 3x - 4
C. y + 4 < 3x - 1
D. y + 4 < 3x + 1
A. 0 - 4 < 3(0) - 1
- 4 < - 1
True
B. 0 - 1 < 3(0) - 4
- 1 < - 4
False
C. y + 4 < 3x - 1
0 + 4 < 3(0) - 1
4 < - 1
False
D. y + 4 < 3x + 1
0 + 4 < 3(0) + 1
4 < 1
False
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
Answer:
44/15 or maybe 2 14/15
Step-by-step explanation:
Answer:

Step-by-step explanation:
