Answer:
175
Step-by-step explanation:
5/24 = 0.208 percentage of defective bolts
scale up to 840 bolts by finding 20.8% of defective bolts
840*20.8 = 175
Answer:
157
Step-by-step explanation:
formula- 2 x 3.14 x 5 squared
6.28 x 5 squared
6.28 x 25
157
Answer:
R = 7.71 ohms
Step-by-step explanation:
By ohm's law: R= V/I
where, R = resistance of wire, V = potential difference, I = electric current
Given: V = 54 and I = 7 A
Plug in the above values in the ohm's law, we get
R = 54 V/7 A
R = 7.71 ohms
Hope this will helpful.
Thank you.
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.
A=B
Method 1:
We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5
B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º ⇒ C=2*40º=80º
Answer:
a=7; A=50º
b=7; B=50º
<span>c=9; C=80º
Method 2:
Law of cosines:
a²=b²+c²-2bcCosA ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º
B=A=50º
A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º
Answer:
</span>a=7; A=50º
b=7; B=50º
<span>c=9; C=80º</span>
Answer:
<em>Choose the first alternative</em>
Step-by-step explanation:
<u>Probabilities</u>
The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions 
and the total number of possible choices 
, i.e.
There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total
We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.
To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5
The total number of possible choices is
The probability is then
Choose the first alternative
