Answer:
1/32768
Step-by-step explanation:
I don't know how to explain it to you. I am sorry.
Answer:
The distance between A and D to the nearest tenth is;
Explanation:
Given the two points;
Applying the distance between two points formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
substituting the given coordinates we have;
![\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AD%3D%5Csqrt%5B%5D%7B%28-3-6%29%5E2%2B%28-2-2%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B%28-9%29%5E2%2B%28-4%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B81%2B16%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B97%7D%20%5Cend%7Bgathered%7D)
Simplifying;
Therefore, the distance between A and D to the nearest tenth is;
Answer:
Step-by-step explanation:
a. H0: μ ≤ 104 Ha: μ > 104
Assuming the data leads to the rejection of the null hypothesis, we would conclude that there is no sufficient statistical evidence to prove that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $104 per month.
b. The type error in this situation would be rejecting the null hypothesis when it is actually true. Rejecting the fact that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $104 per month when it was actually true.
c. Type II error in this case would be failing to reject the null when it is false. Failing to reject the fact that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $104 per month when it is actually not true.
The consequences for these errors might be disastrous including sueing of the accuser party etc.
Answer:
The perimeter is 
Step-by-step explanation:
we know that
The perimeter of the figure is equal to the circumference of a semicircle
plus the perimeter of a square minus the diameter of the circle
so
we have
The diameter of the circle is equal to the length side of the square
substitute
