All categories

3 years ago

6th grade math- x + 2 =? x - 2 =? 2x =? x ÷ 2=? please help asap :((

Mathematics

2 answers:

jeyben [28]3 years ago

5 0

Answer:

x = -2

x = 2

x = ?/2

x = ?(2)

Step-by-step explanation:

<u>For each problem you want to isolate the variable.</u>

For x + 2 you want to move the 2 by subtracting it (since it is being added to the x) from each side. Assuming the other side of the equal sign is 0, the answer is -2.

Same thing for x - 2, isolate by adding the 2 (since it is being subtracted).

For 2x and x ÷ 2 it is a little different. If we assume the opposite side is 0, the answer will be 0 because 0 divided or multiplied by 2 will give you 0. But if the opposite side is a different number, the answer will be that number and then the respected equation for the problem (divide both sides by 2 in 2x because the x is being multiplied by the 2 and multiple both sides by 2 in the x ÷ 2 because the x is being divided by the 2).

Bad White [126]3 years ago

4 0

Give the other guy brainliest he really deserves it

You might be interested in

What’s 5(x+12) equal

juin [17]

Multiply using the distributive property so it would be 5x+60

7 0

3 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .

$\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2$ .

$\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2$ .

Solve this equation for $u$ :

$\displaystyle \frac{u^{2} + 1}{u^{2}} = 2$ .

$u^{2} + 1 = 2 u^{2}$ .

$u^{2} = 1$ .

Given that $0 \le u \le 1$ , $u = 1$ is the only possible solution.

$\cos^{2}{x} = 1$ ,

$x = k \pi$ , where $k\in \mathbb{Z}$ (i.e., $k$ is an integer.)

Given that $0 \le x < 2\pi$ ,

$0 \le k$ .

$k = 0$ or $k = 1$ . Accordingly,

$x = 0$ or $x = \pi$ .

8 0

3 years ago

Read 2 more answers

Isabella bought 4.5 bags of candy for her party baskets. Each bag has 146 pieces of candy. If she has 9 party baskets, how many

Nadusha1986 [10]

73 because 4.5x146= 657 and 657/9= 73

7 0

2 years ago

Read 2 more answers

1+sec^2xsin^2x=sec^2x

Sholpan [36]

1 + sec^2(x)sin^2(x) = sec^2(x)
This becomes
1+tan^2(x) = sec^2(x) which is an identity
You could
1 + sin^2(x)/cos^2(x) = sec^2(x)
then
cos^2(x) + sin^2(x) = cos^2(x)sec^2(x)
1 = 1

4 0

3 years ago

Read 2 more answers

A factory used 478.25 kilograms of tomatoes to make 5 batches of pasta sauce. What quantity of tomatoes did the factory put in e

mylen [45]

The amount of tomatoes put into 1 batch is 95.65 kilograms

4 0

4 years ago