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3 years ago

5

Light A flashes every 8 seconds.

1 answer:

love history [14]3 years ago

8 0

Answer:

it will take flash a to flash 5 times and flash b to only flash 2 times

Step-by-step explanation:

just trust me

You might be interested in

Mari used a thermometer to record temperatures of -3.4 Celsius and 1.6 Celsius . Which temperature in degrees is lower

madam [21]

I think is would be -3.4

3 0

3 years ago

Alexandra and Austin applied to the same university. They looked up the average SAT score of students admitted to that universit

Deffense [45]

Answer:

x= (y+40)-(y-330)

Step-by-step explanation:

According to the information provided, the difference in their scores would be the result of subtracting Austin's SAT score from Alexandra's SAT score.

Then, as Alexandra's SAT score was 40 points above the average score this means that you have to add 40 to the average score to get her result. Also, as Austin's SAT score was 330 points below the average score, this means that you have to subtract 330 from the average score. With this you can write the expression:

x= difference in their scores

y= average score

x= (y+40)-(y-330)

7 0

3 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago

A)$150 at 3 % interest for 2 years

tamaranim1 [39]

Answer:

A) 159.135 = X

B) 2,531.25 = X

C) 6,187.5 = X

D) 831,947.46 = X

Step-by-step explanation:

The following investments are required to be calculated:

A) $ 150 at 3% interest for 2 years

B) $ 750.00 at 1/2% interest for 3 years

C) $ 2,250.00 at 1 3/4% interest for 1 year

D) $ 2,550.00 at 3 1/4 interest for 4 years

Therefore, the following calculations must be performed:

A)

150 x (1 + 0.03) ^ 2 = X

150 x 1.03 ^ 2 = X

159.135 = X

B)

750 x (1 + 0.5) ^ 3 = X

750 x 1.5 ^ 3 = X

2,531.25 = X

C)

2,250 x (1 + 1.75) = X

2,250 x 2.75 = X

6,187.5 = X

D)

2,550 x (1 + 3.25) ^ 4 = X

2,550 x 4.25 ^ 4 = X

831,947.46 = X

4 0

3 years ago

VikaD [51]

Answer:

a. Point S

b. Line segment PT and Line segment ST

c. PSQRU

d. Lines PR and SQ

e. Plane C and Plane QRS

Step-by-step explanation:

7 0

2 years ago